Valeria drives 500 meters up a hill that makes an angle of 15 degrees with the horizontal. To the nearest tenth of a meter, what
horizontal distance has she covered?
1 answer:
Answer:
Approximately 485 meters
Step-by-step explanation:
We can first construct a right triangle, using the 500 m length of hill as our hypotenuse. Using the fact that the cosine of an angle is the ratio of the adjacent side to the hypotenuse, we see that
where x is the horizontal distance covered. Solving for x, we find this horizontal distance to be
so our answer is approximately 485 m.
You might be interested in
4) (a) For these problems, you should take time to familiarize yourself with common fractions that appear on the unit circle. does not appear in the unit circle unless you take the quotient 1/2 divided by sqrt(3)/2 which gives you 1/sqrt(3) which is the same as sqrt(3)/3. So our numerator is 1/2 and our denominator is sqrt(3)/2.
And remember tangent is just sin/cos. So what degree has sinx as 1/2 and and cosx as sqrt(3)/2? Well, 30 degrees does, but 30 degrees is not within the range we are given. That means they are looking for a sinx that gives us -1/2 and a cosx that gives us -sqrt(3)/2 and that is 210 degrees.
And 210 degrees in radians is 7pi/6.
I hoped that made sense.
(b) This is a lot easier. What angle gives us a cos x of -sqrt(3)/2? According to the unit circle, 150 degrees and 210 degrees does. They usually want these in radians, so the answer is 5pi/6 and 7pi/6, respectively.
5) What quadrant is radian measure 5 in?
Well 2pi or roughly 6.28 is a full circle. And 5 is slightly less than 6.28, so it is probably in quadrant IV.
But to be sure let's change 5 radian to degrees:
5 * 180/pi = 900/pi = 286.48 degrees
286.48 degrees is definitely in Q4, so we are correct.
Answer:
D. A(n) = P + (n-1)i*P
Step-by-step explanation:
The formula to calculate the simple interest is:
Replace i by , then
SI = Pni
where n is the number of years.
So, for n-1 years, the simple interest is:
SI = P(n-1)*i
The Total amount is:
A(n) = P + (n-1)i*P