Answer:
lol
Step-by-step explanation:
Answer:
6 possible integers
Step-by-step explanation:
Given
A decreasing geometric sequence
Required
Determine the possible integer values of m
Assume the first term of the sequence to be positive integer x;
The next sequence will be 
The next will be; 
The nth term will be 
For each of the successive terms to be less than the previous term;
then 
must be a proper fraction;
This implies that:
<em>Where 7 is the denominator</em>
<em>The sets of </em><em> is </em>
<em> and their are 6 items in this set</em>
<em>Hence, there are 6 possible integer</em>
Answer:
16
Step-by-step explanation:
Let's represent this with an equation, where x is the first number. The next number must be x+2, because it has to be even, not x+1, and the rest continue the same way:
x+(x+2)+(x+4)+(x+6)+(x+8) = 100
Solve for x.
5x+20 = 100
5x = 80
<u>x = 16</u>
Answer:
2
Step-by-step explanation:
We are given that a decimal number d
d=0.12345678...
Where d is formed by writing in succession all the positive integers in increasing order after decimal point.
We have to find the 100th digit of d to the right of the decimal point.
Place of first digit 1 after decimal=Tenth
Place of second digit 2 after decimal=Hundredth
Place of third digit 3 after decimal=Thousandth
Therefore, 100th digit of d to the right of the decimal point=2
