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3241004551 [841]
2 years ago
12

Find the equation of the line that passes through (-18, -10) and is parallel to the line that passes through (-2, 2) and (-8, 1)

.
A.y =5/6x + 5
B. y=1/6x-7
C. y=6x+98
D. y=-2/3x-5
Mathematics
1 answer:
zhuklara [117]2 years ago
5 0

Answer:

y = 1/6x + 7/3

Step-by-step explanation:

(-2 ,2) and (-8, 1)

Slope=(1-2)/(-8- - 2) = (-1/-6) = 1/6

b = 2 - (1/6)(-2) = 2 - 2/6 = 2 - 1/3 = 7/3

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The required equation of the line is y = -1/2x

<h3>Equation of a line</h3>

The standard equation of a line is expressed as y = mx + b

  • where:
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  • b is the y intercept

Given the coordinate points (0,0) and (4, -2)

Slope  = -2/4 = -1/2

The intercept is 0 since the line pass through the origin

Hence the required equation of the line is y = -1/2x

Learn more on equation of a line here: brainly.com/question/13763238

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