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borishaifa [10]
4 years ago
13

a production manager tests 10 toothbrushes and finds that their mean lifetime is 450 hours. she then designs a sales package for

this type of toothbrush. it states that consumers can expect the toothbrush to last approximately 460 hours. this is an example of what phase of inferential statistics?
Mathematics
2 answers:
Scorpion4ik [409]4 years ago
6 0
The answer was "Probability-based inference", you got apex too?
fiasKO [112]4 years ago
4 0

Answer with explanation:

In Inferential Statistics, for a set of variate or the values in the data set, mean or the other measure of variation, is calculated , then to check the accuracy, or variation in the data set, Several number of times , mean or the other measures of Variation, is calculated for the same data set . And then the hypothesis about the observation which was built earlier or given hypothesis ,if hypothesis found partially true or Incorrect, then the hypothesis is checked,with the help of result obtained, if necessary that is if result do not match,then the, Hypothesis can be or surely, altered.

→→Now,it is given that ,a production manager tests 10 toothbrushes and finds that their mean lifetime is 450 hours,then she designs a sales package for this type of toothbrush. it states that consumers can expect the toothbrush to last approximately 460 hours.

Yes, this is an example of inferential statistics because,Sample size of toothbrushes selected, is equal to 10,which is quite bigger to get the better result,that is to get the mean lifetime,which is 450 hours, and then the hypothesis about the data set is made,which is consumers can expect the toothbrush to last approximately 460 hours.So,Actual Mean lifetime do not vary very much with Hypothetical mean.

So, yes this is a statistical inference called Hypothetical Testing.

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A large container holds 5 gallons of water. It begins leaking at a constant rate. After 10 minutes, the container has 3 gallons
Anna007 [38]
5 - 10 x = 3
10 x = 5 - 3
10 x = 2
x = 10 : 5
x = 0.2
The rate is : 0.2 gallons / minute
5 - t * 0.2 = 0
t * 0.2 = 5
t = 5 : 0.2
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Answer: After 25 minutes the container will be empty.
5 0
3 years ago
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Kaylis [27]
This could be written as y= -2x+6 in standard form
7 0
3 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
The table shows the number of medical clinics and the number of bowling alleys in several cities.
DedPeter [7]

Answer:

Step-by-step explanation:

a) to create a scatter plot for the data, let data for clinics be x and that one for Bowling alleys be y then plot x values with corresponding y values on a graph tool.

<u>x                     y</u>

14                   12

1                      3

6                     6

5                     7

10                    7

6                      8

11                      9

8                      15

6                       7

16                     12

The scatter plot is attached below

b) a cluster is a group of data that is close together. From the plot, the ordered pairs forming a cluster are;

(6,6), (6,7), (5,7), and (6,8)

c) An outlier is a point in a plot which lies very far from the other values. In this case, point its  point (8,15)

d)The linear regression equation is one written in the form of

Y=a+bX where ;

Y=the dependent variable

X=the explanatory variable

a=the intercept, which is the value of y when x=o

b=slope of the line

The formula to apply here is ;

a=(∑y)(∑x²)-(∑x)(∑xy) / n(∑x²)-(∑x)² where n is number of samples

b= n(∑xy)-(∑x)(∑y) / n(∑x²)-(∑x)²

Form a table like below

<u>x                     y               xy               x²                 y²</u>

14                   12              168            196              144

1                      3                 3               1                   9

6                     6                 36            36                 36

5                     7                 35             25                49

10                    7                 70             100              49

6                      8                 48             36              64

11                      9                99             121               81

8                      15               120             64            225

6                       7                42               36              49

16                     12                192            256            144

83                     86              813           871               850------------sum

∑x=83   ∑y=86  ∑xy=813  ∑x²=871  ∑y²=850 and n=10

Applying the formula

a=(∑y)(∑x²)-(∑x)(∑xy) / n(∑x²)-(∑x)²

a=[(86 * 871) - (83*813) ]/ 10 (871-83²)

a=[74906 - 67479] / 10(-6018)

a=[7427] / -60180

a= - 0.1234

b= n(∑xy)-(∑x)(∑y) / n(∑x²)-(∑x)²

b=10(813)-(83*86) / 10 (871)-(83²)

b=[8130-7138] / 8710 -6889

b= 992/1821

b=0.5448

The liner regression equation will be;

Y=a+bX

Y= -0.1234 + 0.5448 X

e) correlation coefficient r is given by;

r= n∑xy - (∑x)(∑y) / √n(∑x²)-(∑x)² × √n(∑y²)-(∑y)²

r=10*813 - (83*86) / √10 *871 -83² ×√10*850 - 86²

r=8130-7138 / √8710-6889 × √8500-7396

r= 992 / (√1821 × √1104)

r=992/ 42.67×33.23

r=992/1417.9

r=0.6996

f) r² is important because it shows you the proportion of the variance of one variable that is predictable from the other variable.

r=0.6996

r²=0.6996² =0.4894

8 0
3 years ago
Read 2 more answers
Write the prime factorization of each number with factoring in increasing order of the base, using exponents for
ale4655 [162]
I don’t know sorry!!!
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