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Advocard [28]
1 year ago
8

When -3v = -18 is solved, the result is:

Mathematics
2 answers:
mel-nik [20]1 year ago
7 0

The result of this mathematical sentence is <u>v=6</u>

<u />

<u />

<h3>First degree equation</h3>

First degree equation is a mathematical sentence - having at least one unknown. Its representation is given by <u>ax + b = 0</u>. To calculate an equation, as it is in the expression in the statement, simply: isolate x and divide the second to the first member.

*Note: Equal signs, the result will be equated as positive.

-3v = -18

v = -18/-3

<u>v = 6</u>

Therefore, the correct value of this equation is <u>v = 6</u>.

rjkz [21]1 year ago
4 0

Answer:

When -3v = -18 is solved, the result is:

21v

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Joe is placing tile in a small rectangular room. The room measures 8 feet by 5.5 feet. If one square foot tiles are sold in pack
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Answer:

4

Step-by-step explanation:

The area, a of the room is 8* 5.5

a = 44 sqaure feet

one square foot of tiles are sold in packages of 12

To get the number of packages needed, simply divide the area of the room by 12

This gives:

44/12 = 4

= 3.67   round up to the nearest whole number

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Answer:  24, 24, 47

<u>Step-by-step explanation:</u>

In order to form a triangle, the sum of two sides must be GREATER than the third side for all combinations.

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23 + 28 = 51 which is NOT greater than 55

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8 + 17 = 25 which is NOT greater than 25

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Read 2 more answers
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
2 years ago
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