How does temperature change as you go from the surface toward the center of the earth?

Physics

1 answer:

Nastasia [14]3 years ago

8 0

Because lava is in the center and lavas hot

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a 12.0L container is filled with a gas to a pressure of 2660 torr at 0°C. At what temp. will the pressure inside the container b

Alexxx [7]

$\frac{p1}{t1} = \frac{p2}{t2}$

Pressure Law: constant volume

Convert all Temperatures to Kelvin

0°C= 273K

$\frac{2660}{273} = \frac{3040}{t2} \\ \\ 3040 \times 273 = t2 \times 2660 \\ \\ 829920 \div 2660 = t2 \\ \\ t2 = 312$

answer= 312Kelvin

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3 years ago

A student conduct an experiment to determine habitation of salt to water affect the density of the water the student feels three

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3 years ago

Why is magnesium the limiting reactant in this experiment

Keith_Richards [23]

Answer:

Explanation:

Magnesium is being oxidized by the oxygen in the air to magnesium oxide. This is a highly exothermic combustion reaction, giving off intense heat and light. The reaction of the combustion of magnesium in oxygen is given below:

2Mg(s) + O2(g) → 2MgO(s)

The stoichiometric factor is 2 moles of magnesium are burned for every 1 mole of oxygen (2mol Mg/1mol O2). If the magnesium strip weighs 1 gram, then there is 0.04 mol of magnesium (1 gram divided by 24.3 grams/mol Mg) available in the reaction. The amount of oxygen required to completely react with the magnesium strip is:

0.04 mol Mg x (1 mol O2 / 2 mol Mg) = 0.02 mol O2 x 16 g/mol O2 = 0.32 gram O2.

The magnesium will burn until consumed entirely. There is much more oxygen available in the atmosphere than needed to consume the magnesium. Thus the magnesium is the limiting reactant because it determines the amount of product formed.

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3 years ago

You have a 6.00 V power supply, and

ollegr [7]

Answer: 0.28 A

Explanation:

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3 years ago

A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le

dangina [55]

Momentum should be conserved. The momentum of both objects must balance with their initial and final momentum.

Let m1 and v1 be the mass and velocity of the bowling ball

And m2 and v2 be the mass and velocity of the bowling pin

(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f

30 kg m/s + (1.5 kg)(0 m/s) = 13kg m/s + 1.5v2f

V2f = 11.33 m/s

<span>So the momentum = 1.5 kg(11.33 m/s) = 17 kg m/s</span>

8 0

3 years ago