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natka813 [3]
2 years ago
11

Please answer all three answers

Physics
1 answer:
Vinvika [58]2 years ago
8 0

Answer:

I. The rock that has the most kinetic energy is rock 3.

II. Rock 3 has the most kinetic energy because it weighs the highest among the rocks i.e it has the highest amount of mass. Also, the mass of an object is directly proportional to the kinetic energy possessed by the object; the higher the mass, the higher the kinetic energy.

III. Kinetic energy is taking place rather than potential energy because the rocks are in motion i.e rolling down a hill.

Explanation:

Energy can be defined as the ability (capacity) to do work. The two (2) main types of energy are;

a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = \frac{1}{2}MV^{2}

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

From the above, we can deduce the following;

I. The rock that has the most kinetic energy is rock 3.

II. Rock 3 has the most kinetic energy because it weighs the highest among the rocks i.e it has the highest amount of mass. Also, the mass of an object is directly proportional to the kinetic energy possessed by the object; the higher the mass, the higher the kinetic energy.

III. Kinetic energy is taking place rather than potential energy because the rocks are in motion i.e rolling down a hill.

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An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. The minimum coefficient of static friction needed for this claim to be possible is 0.7

In an inclined plane, the coefficient of static friction is the angle at which an object slide over another.  

As the angle rises, the gravitational force component surpasses the static friction force, as such, the object begins to slide.

Using the Newton second law;

\sum F_x = \sum F_y = 0

\mathbf{mg sin \theta -f_s= N-mgcos \theta = 0 }

  • So; On the L.H.S

\mathbf{mg sin \theta =f_s}

\mathbf{mg sin \theta =\mu_s N}

  • On the R.H.S

N = mg cos θ

Equating both force component together, we have:

\mathbf{mg sin \theta =\mu_s \ mg \ cos \theta}

\mathbf{sin \theta =\mu_s \ \ cos \theta}

\mathbf{\mu_s = \dfrac{sin \theta }{ cos \theta}}

From trigonometry rule:

\mathbf{tan \theta= \dfrac{sin \theta }{ cos \theta}}

∴

\mathbf{\mu_s =\tan \theta}}

\mathbf{\mu_s =\tan 35^0}}

\mathbf{\mu_s = 0.700}}

Therefore, we can conclude that the minimum coefficient of static friction needed for this claim to be possible is 0.7

Learn more about static friction here:

brainly.com/question/24882156?referrer=searchResults

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Answer:

3 units

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V=539 cubic units

Square base, with edge a=7 units

Slanted edge length: s=14 units

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539 cubic units = (49 square units) h

h= 11 units

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H = 509/120

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Hope u got the answer....pls rate the answer if it is helpful for u....and I'm sorry I could not understand B part so I didn't do it.

Thank you

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