Answer: scenario b and scenario c uses most power
Explanation:
Scenario a:
Work=120J
Time=8 seconds
Power=work ➗ time
Power=120 ➗ 8
Power=15
Power=15 watts
Scenario b:
Work=160J
Time=8 seconds
Power=work ➗ time
Power=160 ➗ 8
Power=20
Power =20 watts
Scenario c:
Work=200J
Time=10 seconds
Power= work ➗ time
Power=200 ➗ 10
Power=20
Power=20 watts
Scenario b and scenario c uses most power
Answer: The given statement is false.
Explanation:
Lightening is defined as steady expansion of air within and surrounding path due to the sudden increase in pressure and temperature that leads to emission of lightning.
Basically, lightning is a state of plasma in which the molecules are very rapidly striking with each other as it also contains positively charged ions and negatively charged electrons.
Lightning always leads to the production of thunder.
Therefore, we can conclude that the statement not every lightning strike produces thunder, is false.
The solution for this problem is:
A velocity of wave is given as V = λ⋅f
V - velocity of wave
f - frequency of wave
λ - wave length
So getting the wave length is:
λ = V/f
λminimum = V / fmaximum
λminimum = 342 / 4200
λminimum = 0.081 m
λmaximum = V/ fminimum
λmaximum = 342 / 28
λmaximum = 12.214 m
Answer:
0.5m/s^2
Explanation:
net force (resultant force) = mass x acceleration
100N/200kg = 0.5
Answer:
v = 2.82 m/s
Explanation:
For this exercise we can use the conservation of energy relations.
We place our reference system at the point where block 1 of m₁ = 4 kg
starting point. With the spring compressed
Em₀ = K_e + U₂ = ½ k x² + m₂ g y₂
final point. When block 1 has descended y = - 0.400 m
Em_f = K₂ + U₂ + U₁ = ½ m₂ v² + m₂ g y₂ + m₁ g y
as there is no friction, the energy is conserved
Em₀ = Em_f
½ k x² + m₂ g y₂ = ½ m₂ v² + m₂ g y₂ + m₁ g y
½ k x² - m₁ g y = ½ m₂ v²
v² = 
let's calculate
v² = 
v² = 2.7 + 5.23
v = √7.927
v = 2,815 m / s
using of significant figures
v = 2.82 m/s
