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larisa [96]
2 years ago
9

Discuss a time when you made an impulsive decision. What was the decision? Why did you make your decision

Physics
1 answer:
Orlov [11]2 years ago
5 0
EXPLANATION: In Summer 2016, I took the decision to buy a car which was impulsive in nature. The car was being offered at a huge stock clearance discount by the dealer and the car was also a limited version much loved by my father. So, to get the last minute deal I bought the car within a week's notice.
ANSWER 2: The decision was taken because the car was limited and it was a huge stock clearance from the dealer's end after which the car's production was stopped and it won't be available. The car being my father's favorite, I wanted to gift it to my dad.
ANSWER 3: The consequence of the decision was I had to get loan from finance company with a tenure of 5 years. The car was well out of my budget. I made a down payment of whatever savings and I got my loan.
ANSWER 4: If the decision was to made all over again, I would prefer to calculate my finance first. I would prefer a used car to buy for me or my dad rather than running for last minute deals from the dealers. The used car will be well within my budget and would also be offering the same features as the new car would have been.

BTW THIS IS NOT MINES :(
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Two blocks are connected as shown in the diagram below. Assume that the ramp is frictionless. Draw the force diagram for the blo
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diagram: see image, x-component: 84.3 N, acceleration: 4.38 m/s^2

Explanation:

(see image for further explanation)

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How much heat is required to convert solid ice with a mass of 985 g and at a temperature of -29.5 °c to liquid water at a temper
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3 years ago
A woman on a bridge 82.2 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an a
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0.71 m/s

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Using y = ut - 1/2gt² where y = height of bridge, u = initial speed of stone = 0 m/s, g = acceleration due to gravity = -9.8 m/s² (negative since it is directed downwards)and t = time it takes the stone to hit the water surface.

So, substituting the values of the variables into the equation, we have

y = ut - 1/2gt²

82.2 m = (0m/s)t - 1/2( -9.8 m/s²)t²

82.2 m = 0 + (4.9 m/s²)t²

82.2 m =  (4.9 m/s²)t²

t²  = 82.2 m/4.9 m/s²

t² = 16.78 s²

t = √16.78 s²

t = 4.1 s

This is also the time it takes the raft to move from 5.04 m before the bridge to 2.13 m before the bridge. So, the distance moved by the raft in time t = 4.1 s is 5.04 m - 2.13 m = 2.91 m.

Since speed = distance/time, the raft's speed v = 2.91 m/4.1 s = 0.71 m/s

5 0
3 years ago
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