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larisa [96]
3 years ago
9

Discuss a time when you made an impulsive decision. What was the decision? Why did you make your decision

Physics
1 answer:
Orlov [11]3 years ago
5 0
EXPLANATION: In Summer 2016, I took the decision to buy a car which was impulsive in nature. The car was being offered at a huge stock clearance discount by the dealer and the car was also a limited version much loved by my father. So, to get the last minute deal I bought the car within a week's notice.
ANSWER 2: The decision was taken because the car was limited and it was a huge stock clearance from the dealer's end after which the car's production was stopped and it won't be available. The car being my father's favorite, I wanted to gift it to my dad.
ANSWER 3: The consequence of the decision was I had to get loan from finance company with a tenure of 5 years. The car was well out of my budget. I made a down payment of whatever savings and I got my loan.
ANSWER 4: If the decision was to made all over again, I would prefer to calculate my finance first. I would prefer a used car to buy for me or my dad rather than running for last minute deals from the dealers. The used car will be well within my budget and would also be offering the same features as the new car would have been.

BTW THIS IS NOT MINES :(
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A flask containing argon gas is connected to an closed-ended mercury manometer. The closed end is under vacuum. If the mercury l
iogann1982 [59]

Answer:

230 torr

Explanation:

Given that

P = 230 mm of Hg

If argon gas and mercury is in equilibrium position then the pressure on the both side will be same .

As we know that

1 torr = 1 mm of Hg

So the pressure of the argon will be 230 torr .

Unit conversion

1 torr = 1 mm of Hg

1 bar = 100 KPa = 10⁵ Pa =  10⁵ N/m² = 0.1 MPa = 0.1 x 10⁶ Pa

5 0
3 years ago
When the net forces equal 0 N, they are which of the following? A. Balanced B. Unbalanced C. A push D. A pull
kvv77 [185]
When the net forces equal 0 Newtons, they are a balanced force.
5 0
3 years ago
An aluminum wire having a cross-sectional area equal to 2.20 10-6 m2 carries a current of 4.50 A. The density of aluminum is 2.7
Kazeer [188]

Answer:

The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

Explanation:

We can find the drift speed by using the following equation:

v = \frac{I}{nqA}

Where:

I: is the current = 4.50 A

n: is the number of electrons

q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C

A: is the cross-sectional area = 2.20x10⁻⁶ m²

We need to find the number of electrons:

n = \frac{6.022\cdot 10^{23} atoms}{1 mol}*\frac{1 mol}{26.982 g}*\frac{2.70 g}{1 cm^{3}}*\frac{(100 cm)^{3}}{1 m^{3}} = 6.03 \cdot 10^{28} atom/m^{3}                  

Now, we can find the drift speed:

v = \frac{I}{nqA} = \frac{4.50 A}{6.03 \cdot 10^{28} atom/m^{3}*1.6 \cdot 10^{-19} C*2.20 \cdot 10^{-6} m^{2}} = 2.12 \cdot 10^{-4} m/s              

Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

I hope it helps you!      

4 0
3 years ago
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