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uysha [10]
3 years ago
9

An extension cord made of two wires of diameter 0.129 cmcm (no. 16 copper wire) and of length 2.7 mm (9 ftft ) is connected to a

n electric heater which draws 17.0 AA on a 120-VV line. How much power is dissipated in the cord?
Physics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

sorry pero di ko yan alam sorry ha na di kita matutulungan

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Strike441 [17]

Answer:

it have to be a

Explanation:

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3 years ago
The graph shows a car's velocity over time. During which time period does the car have the greatest acceleration?
Oksana_A [137]

Answer:

Between 0 and 1 seconds (B)

Explanation:

The velocity of the car over time is represented by the line graphed here

the steeper the line, the greater change in velocity that occurred in a given time frame.

The steepest portion of the line is between 0-1 seconds, which means that the greatest rate of change occurred between 0-1 seconds.

(acceleration is the rate of change)

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The plunger of a syringe is pulled up halfway, as shown in the picture. With the plunger in this position, how does the volume o
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1.48 Assume that the air volume in a small automobile tire is constant and equal to the volume between two concentric cylinders
ICE Princess25 [194]

Answer:

a) 0.018 kg

b) 262 kPa

Explanation:

The volume of the concentric cylinders would be:

V = π/4 * h * (D^2 - d^2)

V = π/4 * 13 * (52^2 - 33^2) = 16500 cm^3 = 0.0165 m^3

The state equation of gases:

p * V = m * R * T

Rearranging:

m = (p * V) / (R * T)

R is 287 J/(kg * K) for air

25 C = 298 K

m0 = 202000 * 0.0165 / (287 * 298) = 0.039 kg

After pumping more air the volume remains about the same, but temperature and pressure change.

30 C = 303 K

m1 = 303000 * 0.0165 / (287 * 303) = 0.057 kg

The mass that was added is

m1 - m0 = 0.057 - 0.039 = 0.018 kg

If that air is cooled to 0 C

0 C  is 273 K

p = m * R * T / V

p = 0.057 * 278 * 273 / 0.0165 = 262000 Pa = 262 kPa

3 0
3 years ago
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