Question

The volume of a gas is 1.15 L at STP. At what temperature would the volume of the gas increase to 1.56 L, if the pressure is decreased to 650 mm og Hg?

Answer 1

A gas occupies 1.15 L at standard pressure and temperature and 1.56 L at 317 K and 650 mmHg, assuming ideal behavior.

What is an ideal gas?

An ideal gas is a gas whose behavior can be explained through ideal gas laws. One of them is the combined gas law.

A gas occupies 1.15 L (V₁) at STP (T₁ = 273,15 K and P₁ = 760 mmHg). We can calculate the temperature (T₂) at which V₂ = 1.56 L and P₂ = 650 mmHg, using the combined gas law.

$\frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2}\\T_2 = \frac{P_2 \times V_2 \times T_1}{P_1 \times V_1} = \frac{650mmHg \times 1.56 L \times 273.15K}{760mmHg \times 1.15 L} = 317 K$

A gas occupies 1.15 L at standard pressure and temperature and 1.56 L at 317 K and 650 mmHg, assuming ideal behavior.

Learn more about ideal gases here: brainly.com/question/15634266

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