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podryga [215]
3 years ago
10

Which describes an atom that has fewer neutrons than protons and more electrons than protons?

Chemistry
1 answer:
Eva8 [605]3 years ago
5 0

Answer:

Option d is correct = Negative ion

Explanation:

We know that an atom consist of electrons, protons and neutrons. Neutrons and protons are present inside the nucleus while electrons are present out side the nucleus. Electron has a negative charge and is written as e⁻. The mass of electron is 9.10938356×10⁻³¹ Kg . While mass of proton and neutron is 1.672623×10⁻²⁷Kg  and 1.674929×10⁻²⁷ Kg  respectively.

Symbol of proton= P⁺  

Symbol of neutron= n⁰  

The number of electron or number of protons are called atomic number while mass number of an atom is sum of protons and neutrons. The  umber of protons and electrons are always equal to make the atom electrically neutral and when an atom loses its valance electron the number of protons increases and thus positive charge increased and atom form cation.

When an atom gain electron negative charge increase because of more number of electron thus atom form negative ion or anion. For example,

Anion formation:

X + e⁻ → X⁻

Cation formation:

X → X⁺ + e⁻

Thus option d is correct option.

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The other two properties that water reacts with halogens to form oxygen gas as one of the products and water decomposes to form hydrogen and oxygen are chemical properties as the chemical composition of water changes in the given reaction.

Therefore the correct answer is b. 1 and 4

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What mass of lithium phosphate would you mass to make 2.5 liter of 1.06 M lithium
alex41 [277]

Answer:

Approximately 3.06 \times 10^{2}\; \rm g (approximately 306\; \rm g.)

Explanation:

Calculate the quantity n of lithium phosphate in V = 2.5\; \rm L of thisc = 1.06\; \rm M = 1.06\; \rm mol \cdot L^{-1} lithium phosphate solution.

\begin{aligned}n &= c \cdot V\\ &= 2.5\; \rm L \times 1.06\; mol \cdot L^{-1}\\ &= 2.65\; \rm mol\end{aligned}.

Empirical formula of lithium phosphate: \rm Li_3PO_4.

Look up the relative atomic mass of \rm Li, \rm P,and \rm O on a modern periodic table:

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  • \rm O: 15.999.

Calculate the formula mass of \rm Li_3PO_4:

M(\rm Li_3PO_4) = 3 \times 6.94 + 30.974 + 4 \times 15.999 = 115.79\; \rm g \cdot mol^{-1}.

Calculate the mass of that n = 2.65\; \rm mol of \rm Li_3PO_4 formula units:

\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}.

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Explanation:

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