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wel
2 years ago
7

Calculate the number of two-person committees that can be formed from a group of 10 people

Mathematics
1 answer:
ioda2 years ago
4 0

Bikash borrowed Rs150,000 from Anish at the rare 21% per year at the end of 9 month. How compound interest should he pay compound half yearly.

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Plz Answer This Mathematics Question??? NEED HELP ASAP
vazorg [7]

Answer:

5.78 * 10^8

Step-by-step explanation:

8.5 * 6.8 = 57.8

5+2=7

In scientific notation the number has to be greater than or equal to 1 and less than ten.

5 0
2 years ago
Read 2 more answers
Endpoints of segment MN have coordinates (0, 0), (5, 1). The endpoints of segment AB have coordinates (1 1/22 , 2 1/4 ) and (−2
Nana76 [90]

Answer: k=18\dfrac{8}{11}.

Step-by-step explanation:

If a line passing through two points, then

Slope=\dfrac{y_2-y_1}{x_2-x_1}

Endpoints of segment MN have coordinates (0, 0) and (5, 1).

Slope of MN =\dfrac{1-0}{5-0}=\dfrac{1}{5}

The endpoints of segment AB have coordinates \left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right) and  \left(-2\dfrac{1}{4} , k\right).

A=\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)=\left(\dfrac{23}{22} ,\dfrac{9}{4}\right)

B=\left(-2\dfrac{1}{4} , k\right)=\left(-\dfrac{9}{4} , k\right).

Slope of AB =\dfrac{k-\frac{9}{4}}{-\frac{9}{4}-\dfrac{23}{22}}

=\dfrac{\frac{4k-9}{4}}{\frac{-99-46}{44}}

=\dfrac{4k-9}{4}\times \dfrac{44}{-145}

=4k-9\times \dfrac{11}{-145}

=\dfrac{44k-99}{-145}

Product of slopes of two perpendicular segments is -1.

Slope of MN × Slope of AB = -1

\dfrac{1}{5}\times \dfrac{44k-99}{-145}=-1

\dfrac{44k-99}{-725}=-1

44k-99=725

44k=725+99

k=\dfrac{824}{44}

k=\dfrac{206}{11}

k=18\dfrac{8}{11}

Therefore, the value of k is k=18\dfrac{8}{11}.

8 0
3 years ago
Read 2 more answers
Can you help me do this Q please :)
goldenfox [79]

Answer:

i didnt get it

Step-by-step explanation:

can you explain

3 0
3 years ago
Algebra 2B U2 L6 Function Operations practice 8-10
Bess [88]

Answer:

1) f(g(0)) = 0

2)  g(f(2)) = 2

3)  g(g(0)) = 8

Step-by-step explanation:

Here, the given functions are:

g(x)  =  3 x +2 and f(x)=  (x-2)/3

1. Now, f(g(x))  =   f(3x+2)

Also,  f(3x+2) = (3x+2 -2) /3 = x

So, f(g(x)) = x

⇒ f(g(0)) = 0

2.  g(f(x))  = g((x-2)/3) = 3((x-2)/3) +2

or, g(f(x)) =   x

⇒  g(f(2)) =   3((2)-2/3) +2   = 2  

or, g(f(2)) = 2

3.  g(g(0)= g( 3 (0) +2)  = g(2)

Now, g(2)  = 3(2) +  2 = 6 +  2 = 8

or, g(g(0)) = 8

6 0
3 years ago
PLEASE HELP ME THIS IS DUE TODAY, I NEED HELP!!!!!!
natita [175]

Answer:

I will explain in comments I just want some points for helping you.

Step-by-step explanation:

sorry that sounds selfish. :'(

4 0
2 years ago
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