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agasfer [191]
2 years ago
9

What is the volume of this rectangular

Mathematics
1 answer:
Basile [38]2 years ago
8 0
<h3>Given:</h3>
  • l= 5 m
  • b= 4 m
  • h= 3 m
<h3>Note that:</h3>
  • l= length
  • b= breadth
  • h= height
<h3>To find:</h3>

The volume of the given rectangular pyramid.

<h3>Solution:</h3>

\large\boxed{Formula:V=\frac{1}{3}lbh}

First, multiply the length (5), breadth (4) and height (3).

5×4×3

= 60 \: cm

Now, divide 60 by 3.

\frac{60}{3}

\large\boxed{V= 20 \: {m}^{3}}

<u>Therefore, the volume of the given rectangular pyramid is 20 cubic meters.</u>

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X + y = 152,<br><br> 8.5x + 12y = 1,656<br><br> How many hats were sold?
Elodia [21]

Answer:

x = 48 and y = 104

Step-by-step explanation:

Given equations are:

x+y = 152\\8.5x+12y=1656

From equation 1:

x = 152-y

Putting the value of y in equation 2

8.5(152-y)+12y = 1656\\1292-8.5y+12y = 1656\\3.5y+1292 = 1656\\3.5y = 1656-1292\\3.5y = 364\\\frac{3.5y}{3.5} = \frac{364}{3.5}\\y = 104

Now we have to put the value of y in one of the equation to find the value of x

Putting y = 104 in the first equation

x+y = 152\\x+ 104 = 152\\x = 152-104\\x = 48

Hence,

The solution of the system of equations is x = 48 and y = 104

The value of variable which was assumed for number of hats, is the total number of hats.

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3 years ago
What is the volume of the cylinder in terms of pi 2 m 6m
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Answer:

6πm³

Step-by-step explanation:

To work out the volume of a cylinder, use the formula πr²h

Next, substitute the known values into the equation (remember that the radius is half of the diameter):

volume = π × 1² × 6

The volume of the cylinder is 6πm³

Hope this helps!

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2 years ago
What is the area of a circle with radius of 3 inches? Use pie =3.14 A .18.84 square roots B .28.26 square roots C .9.42 square r
tatiyna

Answer:

B. 28.26

Step-by-step explanation:

First you have to find the circumference:

R²= 3²=9

Then you multiply your circumference by 3.14 to get you answer:

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x⁶ + 12x⁵ + 60x⁴ + 160x³ + 240x² + 192x + 64

Step-by-step explanation:

We shall expand the brackets;

(x + 2)^6

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x⁶ + 2x⁵ + 4x⁴ + 8x³ + 16x² + 32x + 64

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(1) x⁶ + (6) 2x⁵ + (15) 4x⁴ + (20) 8x³ + (15) 16x² + (6) 32x + (1) 64

x⁶ + 12x⁵ + 60x⁴ + 160x³ + 240x² + 192x + 64

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