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2 years ago

Express sin O as a fraction in simplest terms.

Mathematics

1 answer:

ollegr [7]2 years ago

6 0

To express sin O as a fraction in simplest term is 5/6

<h3>How to determine the expression</h3>

Using the formula:

Sin O = opposite/ hypotenuse

Where opposite = The side directly opposite the angle

hypotenuse = The longest side of the triangle

Sin O = 5 / 6

Therefore, to express sin O as a fraction in simplest term is 5/6

Learn more about the trigonometry here:

brainly.com/question/7331447

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UNO [17]

The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.

<u>Interquartile Range: </u>

Given the Data -> First Quartile = 2, Third Quartile = 5

Interquartile Range = 5 - 2 = 3

<u>Range:</u> 8 - 1 = 7

<u>Variance: </u>

We start by determining the mean,

$\:1+\:2+\:3+\:3+\:3+\:5+\:8 / 7 = 3.57$

n = number of numbers in the set

Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.

$\sum _{i=1}^n\frac{\left(x_i-\bar{x}\right)^2}{n-1},\\\\=> SS/n - 1\\\\=> 31.714/7 - 1\\=> 5.28571$

5.3

<u>Standard Deviation</u>

We take the square root of the variance,

$\sqrt{5.28571} = 2.29906$

2.3

If you are not familiar with variance and standard deviation, just leave it.

3 0

3 years ago

Read 2 more answers

Some one help me please I don’t understand this

3241004551 [841]

Y = log3 27

27 = 3^x

3^3 = 27

so x = 3

7 0

3 years ago

To make 3/4 pound of mixed nuts, how many pounds of cashews would you add to 1/8 pound of almonds and 1/4 pound of peanuts?

Anna11 [10]

you will need 3/8 pounds of peanut.

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3 years ago

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$