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1 year ago

What are the solutions to the quadratic equation below in factored form?

Mathematics

2 answers:

lutik1710 [3]1 year ago

5 0

Answer:

-4/3 or 1/2

Step-by-step explanation:

Explanation::::::::

saw5 [17]1 year ago

4 0

Answer:

$\cfrac{-4}{3}$ and $\cfrac{1}{2}$ .

Step-by-step explanation:

Equation:

$\rm \: \: (2x - 1)(3x + 4) = 0$

Solution:

Set factors equal to zero,that is:

$(2x - 1) = 0 \: \: \: \: \: \: \: \: \: \: \: ...(1)$

$(3x + 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \: ...(2)$

Solving for equation 1:

$2x - 1 = 0$
$2x = 0 + 1$
$2x = 1$

$\boxed{x = \cfrac{ 1}{2} }$

Solving for equation 2:

$3x + 4 = 0$
$3x = 0 - 4$
$3x = - 4$

$\boxed{x = \cfrac{ - 4}{3} }$

Hence,the solutions to the quadratic equation in factored form is $\cfrac{-4}{3}$ and $\cfrac{1}{2}$ .

$\rule{225pt}{2pt}$

Good luck on your assignment!

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