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3 years ago

HELP PLEASE!!! Angle A is circumscribed about circle O, what is the measure of angle D??

Mathematics

1 answer:

viktelen [127]3 years ago

8 0

Answer:

50 exactly 50

Step-by-step explanation:

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I need help with questions two and three I do not understand them at all

rosijanka [135]

1. D bc switch the 1/3 into 3/1, then 4 time 3/1 = 12. Basically 4 times 3 =12
2. D

4 0

2 years ago

Find (a) the slope of the curve at the given point P, and (b) an equation of the tangent line at P: y = 9x^2 + 5 ; P (2,41)

Flauer [41]

Answer:

(a) 36

(b) y = 36x-31

Step-by-step explanation:

(a) dy/dx = 18x

slope of tangent at (2, 41) = 18(2)

= 36

(b) using y-y1 = m(x-x1)

y-41 = 36(x-2)

y = 36x-31

6 0

3 years ago

Given the following 2 equations, state whether these equations are parallel, perpendicular, or neither.

stiks02 [169]

Answer:

Neither

Explanation:

The slope-intercept form of the equation of a line is generally given as;

$y=mx+b$

where m = the slope of the line

b = the y-intercept of the line

Two lines are said to be parallel if they have the same slope. Looking at the two given equations below, we see that the slope of the 1st one, 5/7, is different from the slope of the 2nd one, 7/5;

$\begin{gathered} y=\frac{5}{7}x+14 \\ y=\frac{7}{5}x-20 \end{gathered}$

Two lines are said to be perpendicular if their slopes are negative reciprocals of each other, let's go ahead and compare their slopes;

$\begin{gathered} m_1=\frac{5}{7} \\ m_2=\frac{7}{5} \\ \therefore m_2=\frac{1}{m_1_{}} \end{gathered}$

So the two lines are not perpendicular to each other. It, therefore, means that the correct answer will be Neither.

3 0

1 year ago

(3cosx-4sinx) + (3sinx+4cosx) = 5

Ksenya-84 [330]

(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0

Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)

sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º

The solutions when 0≤x≤360º are: 36.87º and 306.87º.

3 0

3 years ago

Pythagoras was born about 582 bc. Isaac Newton was born in 1643 ad. How many years apart were they born?

malfutka [58]

B.C. counts down to 0, and that's when A.D. starts counting up. That means you can add 582 and 1643, to get their difference. Pythagoras and Newton were born 2,225 years apart.

8 0

3 years ago