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Predict the charge on the monatomic ions formed from the following atoms in binary ionic compounds in the following order: Magne
1 answer:
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Answer:
6,45mmol/L of NaOH you need to add to reach this pH.
Explanation:
CH₃COOH ⇄ CH₃COO⁻ + H⁺ <em>pka = 4,74</em>
Henderson-Hasselbalch equation for acetate buffer is:
5,0 = 4,74 + log₁₀
Solving:
1,82 = <em>(1)</em>
As total concentration of acetate buffer is:
10 mM = [CH₃COOH] + [CH₃COO⁻] <em>(2)</em>
Replacing (2) in (1)
<em>[CH₃COOH] = 3,55 mM</em>
And
<em>[CH₃COO⁻] = 6,45 mM</em>
Knowing that:
<em>CH₃COOH + NaOH → CH₃COO⁻ + Na⁺ + H₂O</em>
Having in the first 10mmol/L of CH₃COOH, you need to add <em>6,45 mmol/L of NaOH. </em>to obtain in the last 6,45mmol/L of CH₃COO⁻ and 3,55mmol/L of CH₃<em>COOH </em>.
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Answer:
Q = 5254.39 J
Explanation:
Given that,
Mass of ethanol, m = 68.8 g
The temperature increases from 40.0°C to 71.3°C.
The specific heat of ethanol is 2.44 j/g°C
We need to find the heat absorbed by the ethanol. We know that the heat absorbed due to the change in temperature is given by :
Put all the values,
So, 5254.39 J of heat is absorbed by Ethanol.