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lubasha [3.4K]
3 years ago
12

When a kettle is placed on the stove and water begins to boil, the hotter water at the bottom begins to rise and the cooler wate

r above it begins to sink. What do we know about the relationship between the hotter water and the cooler water?
Chemistry
2 answers:
4vir4ik [10]3 years ago
8 0

The hotter water is less dense and rises. The cooler water then sinks because it is more dense.

navik [9.2K]3 years ago
5 0

Answer:

Hotter water is less dense than cooler water.

Explanation:

When we increase the temperature of water (we are not talking about ice and water as the density of water increases from 273.15K to 277.15 K, and then start decreasing) its density decreases due to more inter-molecular spaces between the molecules. With increase in temperature the kinetic energy of molecules increases which increases space and thus density decreases (volume increases).

Thus hotter water is less dense and rise up while cooler water is more dense and sinks down.

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Explanation:

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Balanced nuclear equation, what two things must be conserved
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What is the average mass of a single chlorine atom in grams
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Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, th
Gre4nikov [31]

Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

\text{Concentration of NO}=\frac{\text{Moles of }NO}{\text{Volume of solution}}=\frac{0.3152mol}{2.0L}=0.1576M

The given equilibrium reaction is,

                           N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

Initially conc.      0        0           0.1576

At eqm.               (x)       (x)        (0.1576-2x)

The expression of K_c will be,

K_c=\frac{[NO]^2}{[N_2][O_2]}

0.0153=\frac{(0.1576-2x)^2}{(x)\times (x)}

By solving the term, we get:

x=0.0742,0.0839

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

Now we have to calculate the equilibrium concentration of NO.

Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M

Therefore, the equilibrium concentration of NO is, 0.0092 M.

5 0
3 years ago
What occurs in electroplating?
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