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lubasha [3.4K]
3 years ago
12

When a kettle is placed on the stove and water begins to boil, the hotter water at the bottom begins to rise and the cooler wate

r above it begins to sink. What do we know about the relationship between the hotter water and the cooler water?
Chemistry
2 answers:
4vir4ik [10]3 years ago
8 0

The hotter water is less dense and rises. The cooler water then sinks because it is more dense.

navik [9.2K]3 years ago
5 0

Answer:

Hotter water is less dense than cooler water.

Explanation:

When we increase the temperature of water (we are not talking about ice and water as the density of water increases from 273.15K to 277.15 K, and then start decreasing) its density decreases due to more inter-molecular spaces between the molecules. With increase in temperature the kinetic energy of molecules increases which increases space and thus density decreases (volume increases).

Thus hotter water is less dense and rise up while cooler water is more dense and sinks down.

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The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
3 years ago
What is the pOH of a solution that has an H+=7.7x10^-7 M
pentagon [3]

Answer:

Explanation:

Step 1

The question is based on the concept of PH and pOH calculations.

pH is defined as negative logarithmic of hydronium Ion concentration.

while pOH is defined as negative logarithmic of hydroxide ion concentration of the solution.

Step 2

[H+] = 7.7*10-7  M  

pH = -log[H+]  

    = -log ( 7.7*10-7 )

     = 6.12

Step 3

pOH = 14 - pH

   = 14 - 6.11

  = 7.89

4 0
3 years ago
What is the cause of the coral bleaching shown below? A. increased storm severity B. abnormally high water temperature C. ocean
djyliett [7]

Hello,


Your answer is ready.


Answer:

A. increased storm severity.


Please let me know if I am wrong.

~

papaguy

6 0
3 years ago
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Suppose 40.8g of copper(II) acetate is dissolved in 200.mL of a 0.70 M aqueous solution of sodium chromate.
Contact [7]

Answer:

0.42 M

Explanation:

The reaction that takes place is:

  • Cu(CH₃COO)₂ + Na₂CrO₄ → Cu(CrO₄) + 2Na(CH₃COO)

First we <u>calculate the moles of Na₂CrO₄</u>, using the <em>given volume and concentration</em>:

(200 mL = 0.200L)

  • 0.70 M * 0.200 L = 0.14 moles Na₂CrO₄

Now we <u>calculate the moles of Cu(CH₃COO)₂</u>, using its <em>molar mass</em>:

  • 40.8 g ÷ 181.63 g/mol = 0.224 mol Cu(CH₃COO)₂

Because the molar ratio of Cu(CH₃COO)₂ and Na₂CrO₄ is 1:1, we can directly <u>substract the reacting moles of Na₂CrO₄ from the added moles of Cu(CH₃COO)₂</u>:

  • 0.224 mol - 0.14 mol = 0.085 mol

Finally we <u>calculate the resulting molarity</u> of Cu⁺², from the <em>excess </em>cations remaining:

  • 0.085 mol / 0.200 L = 0.42 M

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3 years ago
Predict where the largest jump between successive ionization energies occurs for Rb.
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Answer: confused

Explanation:

8 0
4 years ago
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