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2 years ago

MAY SOMEONE HELP ME PLZZ

Chemistry

1 answer:

makkiz [27]2 years ago

5 0

Answer: Rubber source, temperature, thinkness, thread design, driving pattenrs, weather, etc.

Explanation: There are many variables. Here are a few I would include in a tire lifetime study:

1. Type of rubber, including source

2. Thickness of tire

3. Design of tire thread

4. Life as a function of average speed and road surface

5. Expected outside temperature and wet conditions

6. Driving conditions of speed and both acceleration and deceleration parameters (e.g., tire life when slamming on the brakes or accelerating quickly)

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What is the mole fraction of each component if 3.9 g of benzene (C6H6) is dissolved in 4.6 g of toluene (C7H8)

Savatey [412]

Answer:

Step 1 of 6

(a)

The mass of benzene is , so calculate the moles of benzene as follows:

The mass of toluene is, so calculate the moles of toluene as follows:

Now, calculate the mole fraction as follows:

Therefore, the mole fraction of benzene and toluene is and respectively.

Step 2 of 6

(b)

The formula to calculate the partial pressure is as follows:

Here, is the partial pressure of benzene, is the vapour pressure of pure benzene and is the mole fraction of benzene.

Vapour pressure of pure benzene at is.

Substitute the values in the equation as follows:

Therefore, the partial pressure is .

Step 3 of 6

(c)

Vapor pressure of the solution at 1 atm is .

When the total pressure of the vapour pressure of the mixture is at a temperature, then, the solution boils. It corresponds to the boiling point of the solution.

Calculate the total pressure of the solution at as follows:

Since, the total pressure is less than the atmospheric pressure, the solution will not boil at .

Calculate the total pressure of the solution at as follows:

Since, the total pressure is greater than the atmospheric pressure, the solution will boil at .

Therefore, the boiling point of the solution is .

Step 4 of 6

(d)

Mole fraction of benzene at is calculated as follows:

Mole fraction of toluene at is calculated as follows:

Therefore, the mole fractions of benzene and toluene are and respectively.

Step 5 of 6

(e)

Vapor pressure of benzene at is .

Partial pressure of benzene is calculated as follows:

Vapor pressure of toluene at is .

Partial pressure of toluene is calculated as follows:

Step 6 of 6

Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:

Explanation:

mark me as brainliest

4 0

2 years ago

Read 2 more answers

What is the substance called that is being dissolved in a solution?

Anna [14]

Answer:

Solute - The solute is the substance that is being dissolved by another substance. In the example above, the salt is the solute. Solvent - The solvent is the substance that dissolves the other substance. In the example above, the water is the solvent.

Explanation:

5 0

3 years ago

Read 2 more answers

What geological processes form natural gas

Ivan

Decomposed organic matter ,mud,silt ,and sand

5 0

3 years ago

What would be the total volume of the new solution when it is changed from 0.2 M to 0.04 M?

34kurt

The question is incomplete.

You need two additional data:

1) the original volume
2) what solution you added to change the volume.

This is a molarity problem, so remember molarity definition and formula:

M = n / V in liters: number of moles per liter of solution

To give you the key to answer this kind of questions, supppose the original volumen was 1 ml and that you added only water (solvent).

The original solution was:

V= 1 ml
M = 0.2 M

Using the formula for molarity, M = n / V

n = M×V = 0.2 M × (1 / 10000)l = 0.0002 moles

For the final solution:

n = 0.0002 moles
M = 0.04

From M = n / V ⇒ V = n / M = 0.002 moles / 0.04 M = 0.05 l

Change to ml ⇒ 0.05 l × 1000 ml / l = 50 ml. This would be the answer for the hypothetical problem that I assumed for you.

I hope this gives you all the cues you need to answer similar problems about molarity.

6 0

3 years ago

Read 2 more answers

Fill in the missing data point. Show all calculations leading to an answer.

Aleksandr-060686 [28]

Answer:

1090 mmHg

Explanation:

We know that with gases we must use a Kelvin temperatures, so let’s try a plot of pressure against the Kelvin temperature.

We can create a table as follows

t/°C T/K p/mmHg

10 283 726

20 293 750

40 313 800

70 343 880

100 373 960

150 423 ???

I plotted the data and got the graph in the figure below.

It appears that pressure is a linear function of the Kelvin temperature.

y = mx + b

where x is the slope and b is the y-intercept.

===============

Calculate the slope

I will use the points (275, 700) and (380, 975).

Slope = Δy/Δx = (y₂ - y₁)/(x₂ -x₁) = (975 -700)/(380 – 275) = 275/105 = 2.619

So,

y = 2.619x + b

===============

Calculate the intercept

When x = 275, y = 700.

700 = 2.619 × 275 + b

700 = 720 + b Subtract 720 from each side and transpose.

b = -20

So, the equation of the graph is

y = 2.619x -20

===============

Calculate the pressure at 423 K (150°C)

y = 2.619 × 423 - 20

y = 1110 - 20

y = 1090

At 150 °C, the pressure 1090 mmHg.

The point is approximately at the position of the black dot in the graph.

7 0

3 years ago