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marshall27 [118]
3 years ago
13

MAY SOMEONE HELP ME PLZZ

Chemistry
1 answer:
makkiz [27]3 years ago
5 0

Answer: Rubber source, temperature, thinkness, thread design, driving pattenrs, weather, etc.

Explanation: There are many variables. Here are a few I would include in a tire lifetime study:

1. Type of rubber, including source

2. Thickness of tire

3. Design of tire thread

4. Life as a function of average speed and road surface

5. Expected outside temperature and wet conditions

6. Driving conditions of speed and both acceleration and deceleration parameters (e.g., tire life when slamming on the brakes or accelerating quickly)

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Which describes the current model of the atom? (2 points)
Harman [31]
A. I hope this helps!
4 0
3 years ago
Read 2 more answers
What is the molarity of 60.0 grams of NaOH dissolved in 750 milliliters of water?
Bumek [7]

<u>Answer:</u>

The correct answer option is B) 2.0 M.

<u>Explanation:</u>

We are given the number of grams of NaOH (Sodium Chloride) which are dissolved in 750 milliliters of water and we are to find its molarity.

We know the formula of molarity:

<em>Molarity =  (mass * 1000) / (volume * molecular mass)  </em>

Volume = 750 ml = 750 cm^3

Molecular mass = 40  

Mass = 60 grams

Substituting these values in the above formula:

Molarity = \frac{(60*1000)}{750*40} = 2.0 M

8 0
3 years ago
If the volume of wet gas collected over water is 85.0 mL at 20°C and 760 mm Hg , what is the volume of dry gas at STP conditions
dimulka [17.4K]

Answer: 77.4 mL

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg

P_2 = final pressure of dry gas at STP =  760 mm Hg

V_1 = initial volume of dry gas = 85.0 mL

V_2 = final volume of dry gas at STP = ?

T_1 = initial temperature of dry gas = 20^oC=273+20=293K

T_2 = final temperature of dry gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final volume of wet gas at STP

\frac{742.5mmHg\times 85.0ml}{293K}=\frac{760mmHg\times V_2}{273K}

V_2=77.4mL

Volume of dry gas at STP is 77.4 mL.

5 0
4 years ago
Indicate if the following statements are TRUE (T) or FALSE (F):
Aleks [24]

Answer:

a) T

b) T

c) F

d) F

e) T

f) T

g) T

h) F

I) F

j) F

k) F

l) F

Explanation:

The w/v concentration is obtained from, mass/volume. Hence;

%w/v= 50/1000= 5%

In the %w/w we have;

25g/100 g = 25% w/w

In combustion reaction, energy is given out hence it is exothermic.

Neutralization reaction yields a salt and water

% by mass of carbon is obtained from;

8× 12/114 × 100 = 84.1%

All the ionic substances mentioned have very low solubility in water.

One mole of a substance contains the Avogadro's number of each atom in the compound.

There are two iron atoms so one mole contains 2× 55.85 g of iron.

Some sulphates such as BaSO4 are insoluble in water.

Halides are soluble in water hence NaI is soluble in water.

The equation does not balance with the given coefficients because the number of atoms of each element on both sides differ.

The equation represents a decomposition of calcium carbonate as written.

3 0
3 years ago
PLEASE HELP!!! ON A TIMER, WILL MARK BRAINLIEST
Nadusha1986 [10]

Answer:

<em>Well, Your best answer will be is  2H+ + 2OH-  ->  2H2O but you have to reduce it to H+ + OH-  ->  H2O. </em><em>Good Luck!</em>

8 0
3 years ago
Read 2 more answers
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