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zalisa [80]
4 years ago
12

If 20 ml of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm what's the be

st expression representing the new volume
Chemistry
1 answer:
Inessa [10]4 years ago
6 0
V1= 20 ml=0.020 L
T1 = 10⁰+273⁰= 283 K
T2 = 100⁰ +273⁰ =373 K
P1 = 1 atm
P2 = 10 atm
V2-?

P1V1/T1 = P2V2/T2
(1 atm *0.020 L)/283K = 10 atm*V2/373K
V2 = (1 atm *0.020 L*373K)/(283K *10 atm) =
(1 *0.020 *373)/(283 *10)=<span>0.00264 L</span>≈ 2.6 ml
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How many grams of aluminum sulfate form when 3.90 grams of aluminum is placed in 13.65 grams of sulfuric acid?
SVETLANKA909090 [29]

Answer:

Mass = 17.12 g

Explanation:

Given data:

Mass of Al = 3.90 g

Mass of H₂SO₄ = 13.65

Mass of aluminium sulfate = ?

Solution:

Chemical equation:

3H₂SO₄ + 2Al   →  Al₂(SO₄)₃ + 3H₂

Now we will calculate the number of moles of each reactant.

Moles of H₂SO₄:

Number of moles = mass/ molar mass

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Number of moles = 0.14 mol

Moles of Al:

Number of moles = mass/ molar mass

Number of moles = 3.90 g/ 27 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of aluminium sulfate with sulfuric acid and aluminium.

                           H₂SO₄       :         Al₂(SO₄)₃

                               3            :              1

                           0.14            :          1/3×0.14 = 0.05

                              Al            :           Al₂(SO₄)₃

                               2            :             1

                            0.14           :        1/2×0.14 = 0.07

The number of moles of aluminium sulfate produced by sulfuric acid are less so it will limiting reactant and limit the amount of aluminium sulfate.

Mass of aluminium sulfate:

Mass = number of moles × molar mass

Mass = 0.05 mol × 342.15 g/mol

Mass = 17.12 g

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