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Bas_tet [7]
1 year ago
10

A number cube is rolled 3 times. what is the number of possible outcomes?

Mathematics
1 answer:
Damm [24]1 year ago
5 0

Answer:

please give more info

Step-by-step explanation:

thanks

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Adult tickets to the fall play cost $8 and student tickets cost $4. The drama class sold 20 more adult tickets than student tick
lesya692 [45]

Hi! Welcome to Brainly! Let's solve this word problem together below! :)

Let's write this as a system of equations.

8a+4s=880

a= s+20

Let's plug our a value into the first equation.

8(s+20)+4s=880

8s+160+4s=880

We combine like terms.

12s+160=880

We subtract 160 from both sides.

12s=720

We divide both sides by 12

s=60

Now, we plug this value into the second equation.

a= 60+20

a= 80

Therefore, 80 adult tickets were sold.

I hope this helps! Have a fabulous time here at Brainly! :)

4 0
3 years ago
The school is 3.64 miles from Tonyas house and 1.29 miles from Jamal's house.
SpyIntel [72]

Answer:

2.35 miles

Step-by-step explanation:

5 0
2 years ago
Rob is cooking a cake.The recipe calls for 9 cups of flour.He has already put in 3 cups. How many more cups does he need to put
svetoff [14.1K]

Answer:

9-3= 6 Cups

Step-by-step explanation:

Recipe needs 9 cups of flour, Rob has added 3 cups already so he needs to add 6 more cups to make it 9 cups.

7 0
2 years ago
If a(n)=24 which recursive formula could represent the sequence below? <br> ...,24,88,664,8408,...
sesenic [268]
24= 3*2^3  
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)

8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)

So: 
a(n) = a(n-1) + a(n-2)^2

Lets check: 88+24^2= 664
664+88^2= 8408


3 1
3 years ago
Can someone help me find the value of x?
musickatia [10]
47.60514678





What I did was 28 squared plus b squared equals 38.25 squared and ya......
6 0
2 years ago
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