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2 years ago

The wage rates for a worker are shown below.

Mathematics

1 answer:

s2008m [1.1K]2 years ago

8 0

She was paid $145.

(25x3) + (35x2)
75 + 70
= 145

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if the texting portion of your plan for $15 a month and you said 500 text messages in a month how much does it cost per text

pantera1 [17]

15/500=0.05
$0.05 per text

Hope this helps :)

6 0

2 years ago

Hey please help me if you can I would appreciate it

PolarNik [594]

This is a division problem.
You need to divide 51/2 by 3/2.

$\dfrac{51}{2} \div \dfrac{3}{2} =$

$= \dfrac{51}{2} \times \dfrac{2}{3}$

$= \dfrac{51 \times 2}{2 \times 3}$

$= \dfrac{102}{6}$

$= 102 \div 6$

$= 17$

Answer: Choice D.

6 0

3 years ago

Read 2 more answers

Which of the following is an equation of a line parallel to the equation y=4x+1?

Reil [10]

Answer:

y = 4x + b, where b is any number

Step-by-step explanation:

Adrian, you need to share the possible answer choices.

Every line parallel to y = 4x + 1 has the slope 4.

This is true for any y-intercept, that is, for any b in y = mx + b.

3 0

3 years ago

30 points<br> can somebody please help me<br> question below

Inessa05 [86]

Find the total number of dogs by adding each day:

Total dogs = 23

Percent of dogs: Divide the number of dogs by the total number of patients:

= 23 / 50 = 0.46 x 100 = 46%

Use the given formula to find the standard error:

Standard error = √(0.46*(1-0.46)/50) = 0.07

90%: Find Z value for 90% ( 1.645) multiply by SE:

1.645 x 0.07 = 0.115 = 0.12

Now add and subtract that value from the Percent from above:

46 + 12 = 58%

46-12 = 34%

Answer (34%, 58%)

95%: Find Z value for 95% ( 1.96) multiply by SE:

1.96 x 0.07 = 0.137 = 0.14

Now add and subtract that value from the Percent from above:

46 + 14 = 60%

46-14 = 32%

Answer (32%, 60%)

5 0

3 years ago

The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin

hoa [83]

Answer:

$\frac{dI}{dt}=-0.00016 A/s$

Step-by-step explanation:

We are given that

By ohm's law

$V=IR$

R=389 ohm

I=0.03 A

$\frac{dV}{dt}=-0.06V/s$

$\frac{dR}{dt}=0.07ohm/s$

We have to find rate of change of current I means $\frac{dI}{dt}$

Differentiate the equation w.r.t t

$\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}$

Substitute the values then we get

$-0.06=\frac{dI}{dt}\times 389+0.03\times 0.07$

$-0.06=389\frac{dI}{dt}+0.0021$

$-0.06-0.0021=389\frac{dI}{dt}$

$-0.0621=389\frac{dI}{dt}$

$\frac{dI}{dt}=\frac{-0.0621}{389}=-0.000160 A/s$

Hence, the current I is changing at the rate=-0.00016A/s

4 0

3 years ago