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3 years ago

A cell phone can receive 120 messages per minute. At this rate, how many messages can the phone recieve in 150 seconds

1 answer:

7 0

Hi,

The answer would be 300 messages. To explain, there are 60 seconds in a minute so 120 divided by 60 is 2, so that means 2 words per second. So to get the answer for 150 seconds, you multiply 150 by 2 and get 300.

I hope this helps!

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A 4-L water filter is used to fill 200 mL cups and three 750 mL drink bottles How much water is left in the water filter

Ierofanga [76]

Answer:

1550 mL

Step-by-step explanation:

Total capacity of water = 4 Litre

4 L = 4 * 1000 mL = 4000 mL

200mL cups filled = 1 ; 200 mL

750mL cups filled = 3 ; 750 * 3 = 2250 mL

Total = (200 + 2250) mL = 2450 mL

Water left in filter :

(4000 - 2450) mL = 1550 mL

7 0

3 years ago

Two sides of a triangle measure 8 cm and 12 cm. Which answer CANNOT be the measure of the third side? 4, 8, 12, or 16?

scoundrel [369]

(8+12) > side > |8-12|
20 > side > 4, Then 4 cm is the solution.

Whit a triangle solver: http://triancal.esy.es/?a=8&b=12

4 0

3 years ago

Help me please!!°-°

masya89 [10]

It was complicated but I did it

4 0

3 years ago

A roulette wheel has 38 3838 slots, of which 18 1818 are red, 18 1818 are black, and 2 22 are green. In each round of the game,

Elina [12.6K]

The value of P(R = 3) is 0.2854

<h3>Probability</h3>

Probabilities are used to determine the chances of events.

The given parameters are:

$n = 38$ --- the number of slots
$red = 18$ . --- the number of red slot
$black = 18$ . --- the number of black slot
$green = 2$ . --- the number of green slot

<h3>Individual probabilities</h3>

The probability that the ball lands on a red slot is calculated as:

$p = \frac{18}{38}$

Simplify

$p= \frac{9}{19}$

The probability that the ball does not land on a red slot is calculated as:

$q = \frac{18+2}{38}$

$q = \frac{20}{38}$

Simplify

$q = \frac{10}{19}$

<h3>Binomial probability</h3>

The value of P(R = 3) is then calculated using the following binomial probability formula

$P(R = r) = ^nC_rp^rq^{n-r}$

Where:

$n = 7$

$r = 3$

So, we have:

$P(R = 3) = ^7C_3 \times (9/19)^3 \times (10/19)^{7-3}$

$P(R = 3) = 35 \times (9/19)^3 \times (10/19)^4$

$P(R = 3) = 0.2854$

Hence, the value of P(R = 3) is 0.2854