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hram777 [196]
2 years ago
12

What is the percent yield for the reaction below when

Chemistry
1 answer:
mixer [17]2 years ago
6 0

The percent yield would be 68.3%

<h3>Percent yield</h3>

This is given as:

Percent yield = yield/theoretical yield x 100%

From the equation:

2SO_2(g) + O_2(g) -- > 2SO_3(g)

The mole ratio of the reactants is 2;1

Mole of 705 g SO2 = 705/64 = 11.02 moles

Mole of 80 g O2 = 80/32 = 2.5 moles

O2 is limiting.

Mole ratio of O2 and SO3 = 1:2

Mole equivalent of SO3 = 2.5 x 2 = 5.0 moles

Mass of 5 moles SO3 = 5 x 80 = 400 grams

Percent yield = 400/586 = 68.3%

More on percent yield can be found here: brainly.com/question/17042787

#SPJ1

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Write a balanced chemical equation for the standard formation reaction of solid calcium hydroxide .
AveGali [126]

Calcium Hydroxide (Ca(OH)2) can actually be formed by the reaction of Calcium Oxide (CaO) with water (H2O). The complete balanced chemical reaction is:

<span>CaO  +  H2O  -->  Ca(OH)2</span>

 

<span>The subscript 2 in (OH) means that there are 2 O and 2 H on the product side. Hence, the equation is balanced already.</span>

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3 years ago
Multiply or divide the following<br> me<br> 364.51 m - 63.46 s<br> 3
IgorC [24]

Answer:

In multiplication the answer can contain only the least significant figures as present in any of its values . Here 93.4

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3 years ago
How many moles in 2.87 grams of CO2?
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A 0.67 gram sample of chromium is reacted with sulfur. The resulting chromium sulfide has a mass of 1.2888 grams. What is the em
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Answer:

Cr₂S₃

Explanation:

From the question given above, the following data were obtained:

Mass of chromium (Cr) = 0.67 g

Mass of chromium sulfide = 1.2888 g

Empirical formula =?

Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:

Mass of chromium (Cr) = 0.67 g

Mass of chromium sulfide = 1.2888 g

Mass of sulphur (S) =?

Mass of S = (Mass of chromium sulfide) – (Mass of Cr)

Mass of S = 1.2888 – 0.67

Mass of S = 0.6188 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of Cr = 0.67 g

Mass of S = 0.6188 g

Divide by their molar mass

Cr = 0.67 / 52 = 0.013

S = 0.6188 / 32 = 0.019

Divide by the smallest

Cr = 0.013 / 0.013 = 1

S = 0.019 / 0.013 = 1.46

Multiply by 2 to express in whole number

Cr = 1 × 2 = 2

S = 1.46 × 2 = 3

Therefore, the empirical formula of the compound is Cr₂S₃

5 0
3 years ago
The radii of the atoms become smaller from sodium to chlorine across period 3. This decrease is primarily a result of
Alexxx [7]

Answer:

Nuclear Charge

Explanation:

As we move from sodium to chlorine across, there's increase in atomic number (protons). This also means there is increase in the valence electrons (The valence electrons is denoted by the group).

As the number of protons increases, the nuclear energy also increases. Due to this, the electrons are attracted more strongly and pulled closely to the nucleus.

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