Which principle goes against Bohr's theory and why??

Chemistry

1 answer:

Basile [38]3 years ago

7 0

Answer:

As the Bohr's fixed orbit gives precise information about the radial position and momentum of the orbit, it is against the Heisenberg uncertainty principle. Thus it is inferred that the Heisenberg uncertainty principle goes and the concept Bohr's fixed Orbit are opposite to each other.

Explanation:

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Which element is oxidized in the reaction below? fe(co)5 (l) + 2hi (g) → fe(co)4i2 (s) + co (g) + h2 (g)

Hunter-Best [27]

The element which is oxidized in the reaction below
that is

Fe(Co)5 (l) + 2 Hi (g)= Fe (CO)4 i2(s) +Co (g)+H2 (g) is

Fe this is because fe in Fe(CO)5 compound move from oxidation state of Positive five (5^+) to oxidation state of positive six ( 6^+) in Fe(CO)4i2 compound. fe is oxidized by Hi while Hi itself is reduced by Fe,therefore Fe act as a reducing agent

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3 years ago

Can you help me on this since im struggling on this since day 1

emmasim [6.3K]

Of Ok here is what I am thinking.

Simple replacement means when one element or compound moves out of another element and is replaced by this compound.

For example if you have A+BC ----- AC + B

Most of the time the one which is replaced is found on the right and the left one is going be only one element or compound.

Double replacement means when the two compounds exchange the positive and negative ions. Ok let see this example:

AB+ CD------- AD+ BC
this means if A have + sign and D has - sign they will share to form new compound the same is true for DC. Don't forget that all compounds are formed from positive and negative ions.

QUESTIONS
CUSO4 + NA2S---- CUS + Naso4[ double replacement]
KBR +Pb[CLO3]2------K[clo3]2 +PbBr [ double replacement]
I do not think these questions can be single replacement.
I hope this may helps you.

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3 years ago

How does having no nucleus effect an rcbs life span?

Dvinal [7]

Like all cells without a nucleus it will not carry DNA thus the inability to reproduce its life span will be short

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3 years ago

What would be the voltage (Ecell) of a voltaic cell comprised of Cr (s)/Cr3+(aq) and Fe (s)/Fe2+(aq) if the concentrations of th

zaharov [31]

Answer:

0.35 V

Explanation:

(a) Standard reduction potentials

E°/V

Fe²⁺ + 2e- ⇌ Fe; -0.41

Cr³⁺ + 3e⁻ ⇌ Cr; -0.74

(b) Standard cell potential

E°/V

2Cr³⁺ + 6e⁻ ⇌ 2Cr; +0.74

3Fe ⇌ 3Fe²⁺ + 6e-; -0.41

2Cr³⁺ + 3Fe ⇌ 2Cr + 3Fe²⁺; +0.33

3. Cell potential

2Cr³⁺(0.75 mol·L⁻¹) + 6e⁻ ⇌ 2Cr

3Fe ⇌ 3Fe²⁺(0.25 mol·L⁻¹) + 6e-

2Cr³⁺(0.75 mol·L⁻¹) + 3Fe ⇌ 2Cr + 3Fe²⁺(0.25 mol·L⁻¹)

The concentrations are not 1 mol·L⁻¹, so we must use the Nernst equation

$E = E^{\circ} - \dfrac{RT}{zF}\ln Q$

(a) Data

E° = 0.33 V

R = 8.314 J·K⁻¹mol⁻¹

T = 298 K

z = 6

F = 96 485 C/mol

(b) Calculations:

$Q = \dfrac{\text{[Fe}^{2+}]^{3}}{ \text{[Cr}^{3+}]^{2}} = \dfrac{0.25^{3}}{ 0.75^{2}} =\dfrac{0.0156}{0.562} = 0.0278\\\\E = 0.33 - \left (\dfrac{8.314 \times 298}{6 \times 96485}\right ) \ln(0.0278)\\\\=0.33 -0.00428 \times (-3.58) = 0.33 + 0.0153 = \textbf{0.35 V}\\\text{The cell potential is }\large\boxed{\textbf{0.35 V}}$