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Lelu [443]
2 years ago
13

a ball is rolled uphill a distance of 3 meters before it slows,stops,and begins to roll back. the ball rolls downhill 6 meters b

efore coming to rest against a tree. what is the magnitude of the balls displacement?
Physics
1 answer:
Leona [35]2 years ago
3 0
The answer to your question is 3 meters 
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Ozone in the upper atmosphere absorbs energy in the 210-230 nmnm range of the spectrum. In what region of the electromagnetic sp
kifflom [539]

Answer:

Ultraviolet

Explanation:

The electromagnetic spectrum is divided into a number of parts. One of which is the ultraviolet region. The ultraviolet region is found between the 100 nm - 400 nm band of the electromagnetic spectrum. From the range we just stated now, we can see for certainty that the given range 210 nm - 230 nm lies inside of the 100 nm c 400 nm of the electromagnetic spectrum, that of which is the ultraviolet region.

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3 0
3 years ago
Two identical conducting spheres each having a radius of 0.500 cm are connected by a light, 1.90-m-long conducting wire. A charg
Ivan

Answer: 4.19 N

Explanation: In order to determinate the tension applied on the wire we have to calculate the electric force between the conductor spheres connected by the wire.

As the wire is a conductor the spheres are at same potential so we have:

V1=V2

V1=k*Q1/r1 and V2=k*Q2/r2

where r1=r2, then

Q1=Q2

so the electric force is given by:

F=k*Q^2/d^2  where d is the distance between the spheres.

Finally replacing the values,  we have

F=9*10^9(41*10^-6)^2/(1.9)^2= 4.19 N

8 0
2 years ago
If an object, initially at rest, accelerates at the rate of 25m/s2, what will the magnitude of the displacement be after 50s
Lady bird [3.3K]

Answer:

31250 meters

Explanation:

Given data

Intitially at rest, the velocity will be

u= 0m/s

acceleration a= 25m/s^2

Time= 50s

We know that the expression for the displacement is given as

S=U+ 1/2at^2

S= 0+ 1/2*25*50^2

S= 12.5*2500

S=31250 meters

Hence the displacement is 31250 meters

5 0
2 years ago
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