In ionic bonding, atoms

A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an a

lions [1.4K]

Answer:

Approximately $4.61\times 10^{3}\; {\rm N}$ upwards (assuming that $g = 9.81\; {\rm m\cdot s^{-2}}$ .)

Explanation:

External forces on this astronaut:

Weight (gravitational attraction) from the earth (downwards,) and
Normal force from the floor (upwards.)

Let $(\text{normal force})$ denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

$\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}$ .

Let $m$ denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be $(\text{weight}) = m\, g$ .

Let $a$ denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be $(\text{net force}) = m\, a$ .

Rearrange $\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}$ to obtain an expression for the magnitude of the normal force on this astronaut:

$\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}$ .

3 0

2 years ago

I WILL MARK BRAINLIEST!

xxMikexx [17]

Answer:

Explanation:

The answer is C

7 0

3 years ago

I need help please :)

Masja [62]

Answer:

20

Explanation:

AB, AC, AD, AE, BC, BD, BE, ....

4 0

3 years ago

At the maximum rate of power generation, a small hydroelectric power plant takes a discharge of 16.2 m3/s through an elevation d

Eddi Din [679]

Answer:

Actual rate of power generation = 7,544 KW

Explanation:

given,

discharge of the hydroelectric power plant = 16.2 m³/s

elevation drop = 61 m

head loss through the intakes, penstock, and outlet works = 5.8 m

net head available = 61 - 5.8 = 55.2 m

power available

P = Q× (ρ g H)

P = 16.2 × (1000 × 9.81 × 55.2)

P = 8,772 KW

given efficiency = 86 %

so, Actual rate of power generation = 0.86 × 8772

Actual rate of power generation = 7,544 KW

7 0

3 years ago

In winter the air just above the top bunk bed is warmer than the air just above the bottom bunk bed, because warm air rises. Whi

Anuta_ua [19.1K]

Answer:

Convection

Explanation:

Convection: the lighter warm air moves up and the heavier cold air moves down.

5 0

3 years ago