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salantis [7]
4 years ago
9

In ionic bonding, atoms

Physics
1 answer:
Genrish500 [490]4 years ago
3 0
Can i have more information?
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An object is swung in a horizontal circle on a length of string that is 0.93 m long. Its acceleration is 26.36 m/s2. What is the
Igoryamba

Answer:

The object takes approximately 1.180 seconds to complete one horizontal circle.  

Explanation:

From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration (a), measured in meters per square second, is entirely centripetal and is expressed as:

a = \frac{4\pi^{2}\cdot R}{T^{2}} (1)

Where:

T - Period of rotation, measured in seconds.

R - Radius of rotation, measured in meters.

If we know that a = 26.36\,\frac{m}{s^{2}} and R = 0.93\,m, then the time taken by the object to complete one revolution is:

T^{2} = \frac{4\pi^{2}\cdot R}{a}

T = 2\pi\cdot \sqrt{\frac{R}{a} }

T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }

T \approx 1.180\,s

The object takes approximately 1.180 seconds to complete one horizontal circle.  

7 0
3 years ago
Water at 20oC flows through a long elliptical duct 30 cm wide and 22 cm high. What average velocity, in m/s, would cause the wei
mars1129 [50]

Explanation:

The given data is as follows.

   Fluid is water so, density \rho = 1000 kg/m^{3}

  Weight flow rate = 500 lbf/s = 2224.11 N/sec

  Cross-sectional area (A) = \pi \times \frac{30}{2} \times \frac{22}{2}

                                         = 0.05184 m^{2}

Hence, weight flow rate will be given as follows.

        w = \rho \times g \times A \times V

    2224.11 N/sec = \rho \times g \times A \times V

        V = \frac{2224.11}{1000 \times 9.81 \times 0.05184} m/s

            = 4.373 m/s

Thus, we can conclude that average velocity in the given case is 4.373 m/s.

8 0
3 years ago
Read 2 more answers
When an object with a negative charge is moved from point A to point B through an external electrical field, it gains electrical
Sergio039 [100]

Explanation:

As per the problem,

           \Delta U = (V_{B} - V_{A})(-q) > 0

When q > 0 then -q is a negative charge . Since, change in potential energy (\Delta U) increases.

or,     (V_{A} - V_{B})q > 0

or,      V_{A} > V_{B}

Therefore, both positive and negative charge will move from V_{A} to V_{B} and as V_{B} < V_{A} so both of them move through a negative potential difference.

Thus, we can conclude that the true statements are as follows.

  • The positively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
  • The negatively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).      
4 0
3 years ago
Which of the following best describes pseudoscience?
levacccp [35]

Answer:

A

Explanation:

7 0
3 years ago
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All phase changes are .an example of a phase change is an ice cube melting
masha68 [24]

Answer:

a

Explanation:

a

8 0
3 years ago
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