Answer:
rotation and revolution
Explanation:
out of the four motions the earth is subject to which are: rotation about its axis, revolution around the Sun, processional motion (a slow conical movement
) of the axis, and the solar motion (this refers to the
movement of the whole solar system with space), only two are of any
importance to meteorology as this two causes changes in weather and seasons. The first motion is rotation. Earth rotates on its axis
once every 24 hours. One-half of the Earth’s surface is
therefore facing the Sun at all times. The second motion of Earth is its revolution around the Sun. The revolution around the Sun and the earth tilt on its axis are responsible for changes in seasons. The Earth
makes one complete revolution around the Sun in
approximately 365 1/4 days.
D.
50 mph - 30 mph= 20 mph net velocity
change.
20mph/3600 seconds/hour= .00555 MPS
.0055 miles per second
40 seconds to complete the change
.0055/40= .000138
Answer:
Explanation:
Using Boyles law
Boyle's law states that, the volume of a given gas is inversely proportional to it's pressure, provided that temperature is constant
V ∝ 1 / P
V = k / P
VP = k
Then,
V_1 • P_1 = V_2 • P_2
So, if we want an increase in pressure that will decrease volume of mercury by 0.001%
Then, let initial volume be V_1 = V
New volume is V_2 = 0.001% of V
V_2 = 0.00001•V
Let initial pressure be P_1 = P
So,
Using the equation above
V_1•P_1 = V_2•P_2
V × P = 0.00001•V × P_2
Make P_2 subject of formula by dividing be 0.00001•V
P_2 = V × P / 0.00001 × V
Then,
P_2 = 100000 P
So, the new pressure has to be 10^5 times of the old pressure
Now, using bulk modulus
Bulk modulus of mercury=2.8x10¹⁰N/m²
bulk modulus = P/(-∆V/V)
-∆V = 0.001% of V
-∆V = 0.00001•V
-∆V = 10^-5•V
-∆V/V = 10^-5
Them,
Bulk modulus = P / (-∆V/V)
2.8 × 10^10 = P / 10^-5
P = 2.8 × 10^10 × 10^-5
P = 2.8 × 10^5 N/m²
