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Answer:
The magnitude of the displacement of the soccer player is approximately 77.96 m
The direction of the displacement of the soccer player to the right of the direction directly up the field is approximately 7.37°
Explanation:
The given parameters are;
The distance the soccer player up the field = 60 m
The distance to the right the soccer player runs before shooting goal = 20 m
The direction to the right the soccer player turns from his original direction = 30°
Therefore, by resolution of the displacement, we have
d = 60·j + 20·cos(30°)·j + 20·sin(30°)·i
d = 60·j + 20·cos(30°)·j + 20·sin(30°)·i
d = 60·j + 20·(√3)/2·j + 10·i
d = 10·i + (60 + 10·√3)·j
The magnitude of the displacement of the soccer player = √(10² + (60 + 10·√3)²) ≈ 77.96 m
The direction of the displacement = tan⁻¹(10/(60 + 10·√3)) ≈ 7.37° to the right from the direction directly up the field
Answer:
the power used by the person is 17 W.
Explanation:
Given;
applied force, F = 51 N
distance through which the chair is used, d = 5 m
time of motion, t = 15 s
The power used by the person is calculated as;
Therefore, the power used by the person is 17 W.
Answer:
A, B and F are the right answers
Explanation:
The formula is
A) Increasing both the radius and the speed by a factor of 9
=
<u><em>which means the acceleration will increase by a factor of 9</em></u>
B) Keeping the speed fixed and decreasing the radius by a factor of 9
=
<u><em>which means the acceleration will increase by a factor of 9</em></u>
C) Keeping the radius fixed and increasing the speed by a factor of 9
=
It will increase the acceleration 81 times
D) Keeping the speed fixed and increasing the radius by a factor of 9
=
It will decrease the acceleration by 9 times
E) decreasing both the radius and the speed by a factor of 9
=
It will decrease the acceleration by 9 times
F) Keeping the radius fixed and increasing the speed by a factor of 3
=
<u><em>It will increase the acceleration by 9 times </em></u>
Answer:
a 15.22 m/s
b 45.65 m
Explanation:
Using the same formula,
x = vt, where
x is now 45.65, and
t is 3 s, then
45.65 = 3v
v = 45.65/3
v = 15.22 m/s
See the attachment for the part b. We used the distance gotten in part B, to find question A
