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jeka57 [31]
3 years ago
15

Why people won’t want to live near wind turbines.

Physics
2 answers:
Tatiana [17]3 years ago
8 0

Answer:

People think they ruin landscapes.

Explanation:

This is a common opinion and will be accepted as a point in any essay.

attashe74 [19]3 years ago
4 0
<h2>Answer:</h2><h2>Because they are huge the wind companies are looking to maximise the energy they can produce so they build them big and people in the vicinity feel that they are a blot on the landscape. </h2>

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What is the total distance that the object traveled?
Natasha_Volkova [10]

Answer:

for what?

Explanation:

d=S x T

or

d=vt+1/2at2

srry if wrong but

hope this helps

take care

8 0
3 years ago
Why can a hurricane cause so much destruction?
vodka [1.7K]

Answer:

When a cyclone continues to be out over the ocean, the winds and huge waves that area unit created by the storm become dangerous for ships and alternative water vessels. ... once the cyclone approaches land it will cause an enormous quantity of injury. Flooding caused by storm surges is one among the foremost dangerous components of a cyclone.

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2 years ago
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3. Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 2
Nadusha1986 [10]

Explanation:

Work is the product of force and distance.

W = F×d

W = (22 N) × (16 m)

W = 352 J

7 0
3 years ago
A particle moves so that its position as a function of time in SI units is r = i + (3.0) t2 j + t k. Write expressions for its v
maksim [4K]

Answer:

i - component of V is zero for any value of t  i-e  no motion in this direction

Explanation:

Since

r= i+3t^{2}j+t k

==> V = \frac{d r}{dt}=\frac{d(i+3t^{2}j+kt) }{dt}

=6tj+k

and acceleration is given by taking derivative of velocity w.r.t  t

==> a= \frac{dV}{dt}=\frac{d(6tj+k)}{dt}=6j

so, V=0i+6tj+k

and

a = 0i+6j+k

i - component of V is zero for any value of t  i-e  no motion in this direction

6 0
3 years ago
Please help on this one
Sphinxa [80]

Since this is a projectile motion problem, break down each of the five kinematic quantities into x and y components. To find the range, we need to identify the x component of the displacement of the ball.

Let's break them down into components.

                X                                Y

v₁     32 cos50 m/s           32 sin50 m/s

v₂     32 cos50 m/s                    ?

Δd             ?                                0

Δt              ?                                ?

a                0                         -9.8 m/s²


Let's use the following equation of uniform motion for the Y components to solve for time, which we can then use for the X components to find the range.

                           Δdy = v₁yΔt + 0.5ay(Δt)²

                                0 = v₁yΔt + 0.5ay(Δt)²

                                0 = Δt(v₁ + 0.5ayΔt), Δt ≠ 0

                                0 = v₁ + 0.5ayΔt

                                0 = 32sin50m/s + 0.5(-9.8m/s²)Δt

                                0 = 2<u>4</u>.513 m/s - 4.9m/s²Δt

                 -2<u>4</u>.513m/s = -4.9m/s²Δt

-2<u>4</u>.513m/s  ÷ 4.9m/s² = Δt

                          <u>5</u>.00s = Δt


Now lets put our known values into the same kinematic equation, but this time for the x components to solve for range.

Δdₓ = v₁ₓΔt + 0.5(a)(Δt)²

Δdₓ = 32cos50m/s(<u>5</u>.00s) + 0.5(0)(<u>5</u>.00)²

Δdₓ = 32cos50m/s(<u>5</u>.00s)

Δdₓ = 10<u>2</u>.846


Therefore, the answer is A, 102.9m. According to significant digit rules, neither would be correct, but 103m is the closest to 102.9m so I guess that is what it is.






6 0
3 years ago
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