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slavikrds [6]
3 years ago
15

Find the velocity of a water wave in meters per second with frequency

Physics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

Velocity, v = 0.164 m/s

Explanation:

We have,

Frequency of wave, f = 0.04 Hz

Wavelength, \lambda=4.1\ m

It is required to find the velocity of a water wave. The speed of any wave is given in terms of wavelength and frequency. Its formula is :

v=f\lambda\\\\v=0.04\times 4.1\\\\v=0.164\ m/s

So, the velocity of a water wave is 0.164 m/s.

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A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other. Fi
Tatiana [17]

Answer:

(a) I_A=1/12ML²

(b) I_B=1/3ML²

Explanation:

We know that the moment of inertia of a rod of mass M and lenght L about its center is 1/12ML².

(a) If the rod is bent exactly at its center, the distance from every point of the rod to the axis doesn't change. Since the moment of inertia depends on the distance of every mass to this axis, the moment of inertia remains the same. In other words, I_A=1/12ML².

(b) The two ends and the point where the two segments meet form an isorrectangle triangle. So the distance between the ends d can be calculated using the Pythagorean Theorem:

d=\sqrt{(\frac{1}{2}L) ^{2}+(\frac{1}{2}L) ^{2} } =\sqrt{\frac{1}{2}L^{2} } =\frac{1}{\sqrt{2} } L=\frac{\sqrt{2} }{2} L

Next, the point where the two segments meet, the midpoint of the line connecting the two ends of the rod, and an end of the rod form another rectangle triangle, so we can calculate the distance between the two axis x using Pythagorean Theorem again:

x=\sqrt{(\frac{1}{2}L)^{2}-(\frac{\sqrt{2}}{4}L)  ^{2} } =\sqrt{\frac{1}{8} L^{2} } =\frac{1}{2\sqrt{2}} L=\frac{\sqrt{2}}{4} L

Finally, using the Parallel Axis Theorem, we calculate I_B:

I_B=I_A+Mx^{2} \\\\I_B=\frac{1}{12} ML^{2} +\frac{1}{4}  ML^{2} =\frac{1}{3} ML^{2}

5 0
3 years ago
Energy can be changed from one form to another. Changes in the form of energy are called energy conversions. In an automobile en
Harman [31]

Answer: D <u>(chemical</u>  -> <u>heat</u> -> <u>mechanical</u>)

In automobile engines the petrol/diesel fuel enter in to the engine cylinder, due to spark at the end of the compression, fuel burnt increase the temperature and pressure, develops heat <em>(chemical energy -> heat energy). </em><em>This heat energy acts on a piston develops the work on the crankshaft </em><em>( Heat energy -> Mechanical energy)</em><em>. </em>

4 0
3 years ago
Read 2 more answers
Two titanium spheres approach each other head-on with the same speed and collide elastically. After the collision, one of the sp
kotegsom [21]

Answer:

m2  = 83.3 g

Explanation:

by conservation of momentum principle we have

m_1v_{i1} + m_2v_{i2} = m_2v_{f2}

as both sphere has same speed so v_{i2} = v_{i1}

m_2 = \frac{m_1}[\frac{v_f2}{v_{f1}}+1}

from conservation of kinetic energy principle we have

\frac{1}{2}m_1v^{2}_{i1} + \frac{1}{2}m_2v^{2}_{i2} = \frac{1}{2}m_2v^{2}_f2

v_{f1} = \sqrt {\frac{(m_1+m_2) v^2_i1}{m_2}

v_{f1} =  v_{i2}\sqrt {\frac{(m_1+m_2)}{m_2}

\frac{v_{f1}}{v_{i2}} =\sqrt {\frac{(m_1+m_2)}{m_2}

substituting this value in above equation to get m2 value

m_2 = \frac{m_1}{\sqrt {\frac{(m_1+m_2)}{m_2}+1}}

solving for m2 we  get

m2 = \frac{m_1}{3}

m_1 = 250 g

      =\frac{250}{3}

  m2  = 83.3 g

7 0
3 years ago
Suppose that a pane of crown glass, with a refractive index of 1.52, is immersed in water, which has a refractive index of 1.33.
mylen [45]

Answer:

the angle made by this ray with normal will be 45°

Explanation:

given,                                                      

refractive index of crown glass = 1.52

refractive index of the water = 1.33        

ray of light in water strikes glass at 45°                      

angle subtended by the light when it reenter water = ?                  

When light enter in the glass from the water it get bend toward normal because refractive index of glass is more than water.              

And when ray comes out of the glass it is parallel to the initial light ray.

hence, the angle made by this ray with normal will be 45°

3 0
3 years ago
If the object is placed 6 cm from a concave mirror the image distance 12 cm what is the image discige of the objects move from t
Alika [10]

Answer:

The image distance is -9.3cm.

6 0
2 years ago
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