Write the equation of a line in slope-intercept form, that passes through the point (6,-4) and its parallel to the line y=3x-8
1 answer:
Answer:
Step-by-step explanation:
We'll look for a line with the form of y = mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).
A parallel line will have the same slope as the reference line, For y=3x-8, the slope is 3. We can write:
y =3x + b for the new line. We need a value of b that will cause the line to include point (6,-4). To find a b that will work, simple use the given point in the above equation and solve for b:
y =3x + b
-4 =3(6) + b for (6,-4)
-4 =18 + b
b = -22
The parallel line that goes through point (6,-4) is y = 3x - 22
See the attached graph.
You might be interested in