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IRINA_888 [86]
3 years ago
15

What is the surface area of the pyramid formed from the net shown here? The triangles are equilateral, and each triangle has a h

eight of 5.2 centimeters.

Mathematics
1 answer:
azamat3 years ago
3 0

Answer:

62.4 square centimeters

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The surface area of the triangular pyramid is equal to the area of the triangular base plus the area of its three lateral triangular faces

In this problem the triangles are equilateral, that means, the

surface area is equal to the area of four congruent equilateral triangles

so

A=4[\frac{1}{2}(b)(h)]

we have

b=6\ cm\\h=5.2\ cm

substitute

A=4[\frac{1}{2}(6)(5.2)]=62.4\ cm^2

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H is the number of hours worked. So the expression 200h+250 is 200 times the number of hours plus 250.

Here's a few computations using different values for h

1 hour --> (200)(1)+250 = 450
2 hours --> (200)(2) + 250 = 650
3 hours --> (200)(3)+250 = 850
10 hours --> (200)(10)+250 = 2250

As you can see the 250 is fixed. It gets added to the cost no matter how many hours the lawyer works. This is most likely a flat fee. Just to meet the lawyer you pay $250.

The 200 gets multiplied by the hours worked. So the 200 is an hourly rate. The more hours the lawyer works, the more he gets paid because this part of the expression depends on the hours worked.

Thus, an interpretation of the expression 200h + 250 is that the lawyer charges a fee of $250 per consultation and an additional $200 per hour on top of that.
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4 years ago
Stephen makes wooden shelves for his room he starts with a board that is 20 feet long.Stephen wants to make the shelves 3/4 foot
jek_recluse [69]

The number of shelves stephen can make is approximately 27

<h3><u>Solution:</u></h3>

Given that Stephen makes wooden shelves for his room

Stephen wants to make the shelves 3/4 foot long

He starts with a board that is 20 feet long

To find: number of shelves he can make

So the number of shelves stephen can make can make is found out by dividing 20 feet long board by 3/4 foot long

\text {number of shelves }=\frac{\text { total length of board stephen has }}{\text { length of each board }}

\text {number of shelves }=\frac{20}{3 / 4}=\frac{20}{0.75}=26.6

So the number of shelves stephen can make is approximately 27

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The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9
Eva8 [605]

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that \mu = 8.9, \sigma = 2.9

Sample of 37:

This means that n = 37, s = \frac{2.9}{\sqrt{37}}

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}

Z = -0.53

Z = -0.53 has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

Z = \frac{X - \mu}{s}

Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}

Z = -3.08

Z = -3.08 has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

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