Answer
given,
mass of jogger = 67 kg
speed in east direction = 2.3 m/s
mass of jogger 2 = 70 Kg
speed = 1.3 m/s in 61 ° north of east.
jogger one
![P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}](https://tex.z-dn.net/?f=P_2%20%3D%2070%5Ctimes%20v%20cos%20%5Ctheta%20%5Chat%7Bi%7D%20%2B70%5Ctimes%20v%20sin%20%5Ctheta%20%5Chat%7Bj%7D%20)
now
P = P₁ + P₂
magnitude
![P = \sqrt{198.22^2 + 79.59^2}](https://tex.z-dn.net/?f=P%20%3D%20%5Csqrt%7B198.22%5E2%20%2B%2079.59%5E2%7D)
![P =213.60 kg.m/s](https://tex.z-dn.net/?f=P%20%3D213.60%20kg.m%2Fs)
![\theta = tan^{-1}\dfrac{79.59}{198.22}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%5Cdfrac%7B79.59%7D%7B198.22%7D)
![\theta = 21.87](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2021.87)
the angle is
north of east
2.c
3.b
1.a
......................................................................................................................................................
C- 10ft. Hope this helped. Have a great day! :D
Answer:
9.96x10^-20 kg-m/s
Explanation:
Momentum p is the product of mass and velocity, i.e
P = mv
Alpha particles, like helium nuclei, have a net spin of zero. Due to the mechanism of their production in standard alpha radioactive decay, alpha particles generally have a kinetic energy of about 5 MeV, and a velocity in the vicinity of 5% the speed of light.
From this we calculate the speed as
v = 5% 0f 3x10^8 m/s (speed of light)
v = 1.5x10^7 m/s
The mass of an alpha particle is approximately 6.64×10−27 kg
Therefore,
P = 1.5x10^7 x 6.64×10^−27
P = 9.96x10^-20 kg-m/s
Answer:
ANSWER BELOW I
I
V
Remember that w=mg where w is weight in Newtons, m is mass in kilograms, and g is gravity in
m/s2
. For example, for Earth, 445 N = 45.4 × 9.8
m/s2
:Notice that the x-axis values will be gravity in
m/s2
, which is already given in the table, and the y-axis values will be the weight in Newtons. Remember to round your weights to a whole number, and to enter the points starting with the lowest gravity (moon, then Mars, then Venus, then Earth).