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juin [17]
2 years ago
8

PLS ANSWER WITH EXPLANATION OR SOLUTION (WILL GIVE 50 PTS)

Physics
1 answer:
Fed [463]2 years ago
3 0

Answer:

\underline{ \boxed{F_m =  3.35 { \times 10}^{ - 2} N}}

Explanation:

since \: in \: this \: case \to \: \underline{ v }\: is \perp \: to \:\underline{ q} \\ then \: the \: magnetic \: force \: (F_m) \: is \:  max = qvB \sin(90)  \\ F_m = qvB  \times (1) = qvB \\ hence \to \\ F_m = qvB  \\ where \\  \: q = 0.75 C : v = 235m {s}^{ - 1}  : B = 1.9 { \times 10}^{ - 4} T  \\ therefore \to \\ F_m = 0.75 \times 235 \times 1.9 { \times 10}^{ - 4} \\ F_m = 176.25 \times 1.9 { \times 10}^{ - 4} \\ F_m = 0.0334875  = 3.35 { \times 10}^{ - 2} N \\ \boxed{F_m =  3.35 { \times 10}^{ - 2} N}

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MissTica
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8 0
3 years ago
Suppose we wrap a string around the surface of a uniform cylinder of radius 38.0 cm that is supported by an axle passing through
liraira [26]

Answer:

Angular acceleration = 23.68 rad / s²

Explanation:

Given that,

acceleration = 9m/s²

Therefore acceleration of string is 9m/s²

since string is constant in length

cylinder of radius 38.0 cm = 0.38m

Angular acceleration = a / r

Angular acceleration = 9 / 0.38

                                   = 23.68 rad / s²

Angular acceleration = 23.68 rad / s²

4 0
3 years ago
As a way of determining the inductance of a coil used in a research project, a student first connects the coil to a 5.62 V batte
Reptile [31]

Answer:

Its inductance L = 166 mH

Explanation:

Since a current, I = 0.698 A is obtained when a voltage , V = 5.62 V is applied, the resistance of the coil is gotten from V = IR

R = V/I = 5.62/0.698 = 8.052 Ω

Since we have a current of I' = 0.36 A (rms) when a voltage of V' = 35.1 V (rms) is applied, the impedance Z of the coil is gotten from

V₀' = I₀'Z where V₀ = maximum voltage = √2V' and I₀ = maximum current = √2I'

Z = V'/I' = √2 × 35.1 V/√2 × 0.36 V = 97.5 Ω

WE now find the reactance X of the coil from

Z² = X² + R²

X = √(Z² - R²)

= √(97.5² - 8.05²)

= √(9506.25 - 64.8025)

= √9441.4475

= 97.17 Ω

Now, the reactance X = 2πfL where f = frequency of generator = 93.1 Hz and L = inductance of coil.

L = X/2πf

= 97.17/2π(93.1 Hz)

= 97.17 Ω/584.965 rad/s

= 0.166 H

= 166 mH

Its inductance L = 166 mH

5 0
3 years ago
Calculate the critical angle for light going from Glycerine to air.
Georgia [21]
The refractive index for glycerine is n_g=1.473, while for air it is n_a = 1.00.

When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
\theta_c = \arcsin ( \frac{n_2}{n_1} )
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
\theta_c = \arcsin ( \frac{1.00}{1.473} )=42.8^{\circ}
6 0
2 years ago
Describe the changes of motion when marble is moved from one viewpoint to another.
slavikrds [6]

Answer:

Explanation:

according to Newton First Law of Motion (Law of Inertia); An object at rest will stay at rest, forever, as long as nothing pushes or pulls on it. An object in motion will stay in motion, traveling in a straight line, forever, until something pushes or pulls on it.

the marble will move in a straight line

5 0
3 years ago
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