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juin [17]
2 years ago
8

PLS ANSWER WITH EXPLANATION OR SOLUTION (WILL GIVE 50 PTS)

Physics
1 answer:
Fed [463]2 years ago
3 0

Answer:

\underline{ \boxed{F_m =  3.35 { \times 10}^{ - 2} N}}

Explanation:

since \: in \: this \: case \to \: \underline{ v }\: is \perp \: to \:\underline{ q} \\ then \: the \: magnetic \: force \: (F_m) \: is \:  max = qvB \sin(90)  \\ F_m = qvB  \times (1) = qvB \\ hence \to \\ F_m = qvB  \\ where \\  \: q = 0.75 C : v = 235m {s}^{ - 1}  : B = 1.9 { \times 10}^{ - 4} T  \\ therefore \to \\ F_m = 0.75 \times 235 \times 1.9 { \times 10}^{ - 4} \\ F_m = 176.25 \times 1.9 { \times 10}^{ - 4} \\ F_m = 0.0334875  = 3.35 { \times 10}^{ - 2} N \\ \boxed{F_m =  3.35 { \times 10}^{ - 2} N}

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Explanation:

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When a high-energy proton or pion traveling near the speed of light collides with a nucleus, d=2.5\times 10^{-15}\ m

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Let t is the time interval required for the strong interaction to occur. The speed is given by :

c=\dfrac{d}{t}

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Two masses —m1 and m2— are connected by light cables to the perimeters of two cylinders of radii r1 and r2 respectively, as show
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Answer:

Part a)

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Part b)

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T = 176.6 N

Explanation:

Part a)

When m1 and m2 both connected to the cylinder then the system is at rest

so we can use torque balance here

m_1g r_1 = m_2 g r_2

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Part b)

When block m_2 is removed then system becomes unstable

so force equation of mass m1

m_1g - T = m_1 a

also we have

T r_1 = I\alpha

now we have

m_1g = \frac{I a}{r_1^2} + m_1 a

a = \frac{m_1g}{\frac{I}{r_1^2} + m_1}

a = \frac{20 (9.81)}{\frac{45}{0.5^2} + 20}

a = 0.981 m/s^2

so angular acceleration is given as

\alpha = \frac{a}{r_1}

\alpha = \frac{0.981}{0.5}

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Part c)

Tension in the rope is given as

T = \frac{I\alpha}{r_1}

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3 years ago
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ololo11 [35]

Answer:

2 moles

Explanation:

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