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3 years ago

PLS ANSWER WITH EXPLANATION OR SOLUTION (WILL GIVE 50 PTS)

Physics

1 answer:

Fed [463]3 years ago

3 0

Answer:

$\underline{ \boxed{F_m = 3.35 { \times 10}^{ - 2} N}}$

Explanation:

$since \: in \: this \: case \to \: \underline{ v }\: is \perp \: to \:\underline{ q} \\ then \: the \: magnetic \: force \: (F_m) \: is \: max = qvB \sin(90) \\ F_m = qvB \times (1) = qvB \\ hence \to \\ F_m = qvB \\ where \\ \: q = 0.75 C : v = 235m {s}^{ - 1} : B = 1.9 { \times 10}^{ - 4} T \\ therefore \to \\ F_m = 0.75 \times 235 \times 1.9 { \times 10}^{ - 4} \\ F_m = 176.25 \times 1.9 { \times 10}^{ - 4} \\ F_m = 0.0334875 = 3.35 { \times 10}^{ - 2} N \\ \boxed{F_m = 3.35 { \times 10}^{ - 2} N}$

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Help ASAP! I'm taking a test! thank you all xoxo

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Answer:

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3 years ago

Suppose that we use a heater to boil liquid nitrogen (N2 molecules). 4480 J of heat turns 20 g of liquid nitrogen into gas. Note

love history [14]

Answer:

The energy is $9.4\times10^{-21}\ J$

(a) is correct option

Explanation:

Given that,

Energy = 4480 j

Weight of nitrogen = 20 g

Boil temperature = 77 K

Pressure = 1 atm

We need to calculate the internal energy

Using first law of thermodynamics

$Q=\Delta U+W$

$Q=\Delta U+nRT$

Put the value into the formula

$4480=\Delta U+\dfrac{20}{28}\times8.314\times77$

$\Delta U=4480-\dfrac{20}{28}\times8.314\times77$

$\Delta U=4022.73\ J$

We need to calculate the number of molecules in 20 g N₂

Using formula of number of molecules

$N=n\times \text{Avogadro number}$

Put the value into the formula

$N=\dfrac{20}{28}\times6.02\times10^{23}$

$N=4.3\times10^{23}$

We need to calculate the energy

Using formula of energy

$E=\dfrac{\Delta U}{N}$

Put the value into the formula

$E=\dfrac{4022.73}{4.3\times10^{23}}$

$E=9.4\times10^{-21}\ J$

Hence, The energy is $9.4\times10^{-21}\ J$

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3 years ago

It is desired to create a particle of mass 7920 MeV/c^2 in a head-on collision between a proton and an antiproton (each having a

Olegator [25]

Answer:

$v=0.9714c$

Explanation:

The kinetic energy possessed by particles will be

$K.E=\frac{1}{2}Mc^2$

where,

M is the mass of the particle (7920938.3 MeV/c²)

c is the speed of the light

Also,

energy of the proton particle = $\frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}$

where,

v is the velocity

m_p is the mass of the proton (938.3 MeV/c²)

since the energy is equal

thus,

$\frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}=\frac{1}{2}Mc^2$

$1-\frac{v^2}{c^2}=[\frac{2m_p}{M}]^2$

substituting the values in the above equation, we get

$1-\frac{v^2}{c^2}=[\frac{2\times 938.3 }{7920}]^2$

$v=0.9714c$

Hence,<u> the speed necessary for the specified condition to occur is </u><u>0.9714 times the speed of the light</u>

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3 years ago

The windshield of a speeding car hits a hovering insect. Consider the time interval from just before the car hits the insect to

HACTEHA [7]

Answer:

A. False

B True

C. False

D.False

E. True

F. False

G. False

H. False

I. True

Explanation:

A. False: The system being analyzed consists of the bug and the car. These are the two bodies involved in the collision.

B. True: The system being analyzed consists of the bug and the car

C. False: The magnitudes of the change in velocity are different from the car and the bug. The velocity of the bug changes from 0 to the velocity of the car, while there is no noticeable change in the velocity of the car

D.False: There is barely any change in the momentum of the car since the mass of the bug is very small.

E. True: Since the mass of the bug is small, and was initially at rest, the magnitude of the change in monentum will be large because the new velocity will be that of the car.

F. False: The system being analyzed consists of the bug and the car. Those are the two bodies involved in the collision

G. False: The car barely changes in velocity since the mass of the bug is small.

H. False: The car barely changes in momentum because the collision does not affect its speed so much. on the other hand the momentum change of the bug is large since its mass is small.

I. True: The bug which was initially at rest will begin moving with the velovity of the speeding car, while the car barely changes in its velocity

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3 years ago

Which of the following statements is true concerning mechanical waves and electromagnetic waves?

Over [174]

Answer:

Explanation:

Electromagnetic spectrum includes visible light which we see all the time reflecting off objects to give them colours, mechanical waves like sound require something to move in, its the reason why people say you can't scream in space because space is a giant vacuum. No not the kind you use to clean up the mess you made from breakfast. The kind that has no air. So sound can be heard on earth as it is not a vacuum, air moves freely and transfers sounds vibrations all around you to be absorbed by walls and other stuff in comes in contact with.

Extra information:

Sound travels further in water because the molecules are closer together meaning that transferring the energy is easier. This is how Blue wales can communicate from hundreds of miles away.

3 0

3 years ago