The question is incomplete. The complete question is :
A plate of uniform areal density 
is bounded by the four curves:
where x and y are in meters. Point 
has coordinates 
and 
. What is the moment of inertia 
of the plate about the point ?
Solution :
Given :
and , 
, 
.
So,
, 
![$I=2 \int_1^2 \left( \left[ (x-1)^2y+\frac{(y+2)^3}{3}\right]_{-x^2+4x-5}^{x^2+4x+6}\right) \ dx$](https://tex.z-dn.net/?f=%24I%3D2%20%5Cint_1%5E2%20%5Cleft%28%20%5Cleft%5B%20%28x-1%29%5E2y%2B%5Cfrac%7B%28y%2B2%29%5E3%7D%7B3%7D%5Cright%5D_%7B-x%5E2%2B4x-5%7D%5E%7Bx%5E2%2B4x%2B6%7D%5Cright%29%20%5C%20dx%24)
So the moment of inertia is 
.
Answer:
final equilibrium temperature is 65.02 ◦C
Explanation:
Given data
milk = 12 g
temp milk = 7◦C
coffee = 175 g
coffee temp = 69◦C
to find out
final equilibrium temperature
solution
we apply here equilibrium condition i.e m c ΔT
milk mass × c × ΔT = coffee mass × c × ΔT
12 × 1 × (T- 7) = 175 × 1 × ( 69- T)
12T - 84 = 12075 - 175 T
187 T = 12159
T = 65.02
so final equilibrium temperature is 65.02 ◦C
Answer:
A wavelength is a measure of distance between two consecutive crests or trough. So , the unit of wavelength is same as unit of distance. I.e metre
The third option looks easier
