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3 years ago

Calculate the amount of work for a car that exerts 10N and travels a distance of 5 meters.

Physics

2 answers:

lesya [120]3 years ago

4 0

Answer:

50 j

Explanation:

W=Force*distance

W=10N*5M

W=50 NM

n*m = joules so you can say 50joules

Andreas93 [3]3 years ago

4 0

50 J

Explanation......

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To get an idea of the size of magnetic fields at the atomic level, consider the magnitude of the magnetic field due to the elect

artcher [175]

Answer:

The magnetic field is 14.08 T.

Explanation:

Given that,

Speed of electron $v=2.2\times10^{6}\ m/s$

Distance $d =0.5\times10^{-10}\ m$

Suppose we need to find the magnetic field at the location of the proton

We need to calculate the magnetic field

Using formula of magnetic field

$B = \dfrac{\mu_{0}I}{2r}$ ....(I)

Using formula of current

$I=\dfrac{q}{T}$

Using formula of time

$T= \dfrac{2\pi r}{v}$

Put the value of current and time in equation (I)

$B=\dfrac{\mu \times q\times v}{2\pi r\times2r}$

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times1.6\times10^{-19}\times2.2\times10^{6}}{4\pi\times(0.5\times10^{-10})^2}$

$B=14.08\ T$

Hence, The magnetic field is 14.08 T.

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3 years ago

what is the ratio of ey,final, the maximum value of the y-component of the electric field immediately following the last polariz

OleMash [197]

That ratio is 2 .

<h3>What is ratio?</h3>

A ratio is the comparison of the two numbers bydivision.

Taking the first two outputs, or the -1/8 and -1/4, we can divide not the second one by the first one to find the

ratio:

-1/4-1/8

When dividing fractions, we multiply by the reciprocal:

-1/4x-8/1

To multiply fractions, multiply straight across:

(-1x-8)/(4x1) 8/4=2

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1 year ago

Who would you be friends with

Firdavs [7]

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Explanation:

6 0

4 years ago

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The diagram shows a wave. The quantity shown is the amplitude. This quantity is directly proportional to which of these other qu

Katen [24]

As we know that frequency and wavelength are dependent on each other

and this is given by

$f = \frac{c}{\lambda}$

here we know that

$\lambda$ = wavelength

f = frequency

c = speed of wave

while for energy and intensity of wave we know that

Energy = $KA^2$

here A = amplitude of wave

so energy directly depends on amplitude of wave

so correct answer will be

<em>A) Energy</em>

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3 years ago

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What is the net force needed to accelerate a 5 kg object at 3 m/s2? Suppose that in this situation you discovered that there is

Rudik [331]

The Force need to accelerate the object is by 3 m/s² is 15 N. Suppose a friction force of 5 N acts on the motion of the object, the force needed to be applied to the object is 20 N

<h3>Force:</h3>

This can be defined as the product of the mass and the acceleration of a body. The S.I unit of force is kgm/s or Newton(N)

To calculate the force needed to accelerate a mass of 5 kg object at 3 m/s² we use the formula below.

Formula:

F = ma........ equation 1

Where:

F = Net force needed to accelerate the object
m = mass of the object
a = acceleration of the object

From the question,

Given:

m = 5 kg
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Substitute these values into equation 1

F = 5(3)
F = 15 N

Suppose a frictional force of 5 N acts on the motion, The force applied is

F = F'+ma............ Equation 2

Where:

F = Frictional force = 5N

Substitute into equation 2

F = 5(3)+5
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F = 20 N.

Hence, The Force need to accelerate the object is by 3 m/s² is 15 N. Suppose a friction force of 5 N acts on the motion of the object, the force needed to be applied to the object is 20 N

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3 years ago