Question

Question 2 Write the following paragraph proof as a two-column proof. Given: AB = CD and BC = DE Prove: AC = CE A B C D E We're given that AB = CD. By the addition property of equality, we add BC to both sides of the equation to get AB + BC = CD + BC. Since we're also given that BC = DE, we use the substitution property of equality to replace BC with DE on the right side of the equation. So, AB+ BC = CD + DE. Next, by segment addition, we get that AB + BC is equal to AC and that CD + DE is equal to CE. Finally, we use the substitution property of equality on the equation AB + BC = CD + DE to replace AB + BC with AC and CD + DE with CE to get that AC = CE. Type the correct answer in the box. BIUX² X₂ 14pt === Statements Reasons B.
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Answer 1

Answer: See below

Step-by-step explanation:

Given:

AB = CD and BC = DE

To prove:

AC = CE

            Statements                                       Reasons

1. AB = CD                                                   Given
2. AB + CB = CD + BC                Addition property of equality
3. AB + BC = CD + DE                          Given: BC = DE
4. AC = CE          By segment addition: AB + BC = AC and CD + DE = CE  

Therefore, AC = CE has been proved