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DENIUS [597]
2 years ago
9

Question 2 Write the following paragraph proof as a two-column proof. Given: AB = CD and BC = DE Prove: AC = CE A B C D E We're

given that AB = CD. By the addition property of equality, we add BC to both sides of the equation to get AB + BC = CD + BC. Since we're also given that BC = DE, we use the substitution property of equality to replace BC with DE on the right side of the equation. So, AB+ BC = CD + DE. Next, by segment addition, we get that AB + BC is equal to AC and that CD + DE is equal to CE. Finally, we use the substitution property of equality on the equation AB + BC = CD + DE to replace AB + BC with AC and CD + DE with CE to get that AC = CE. Type the correct answer in the box. BIUX² X₂ 14pt === Statements Reasons B.
​

Mathematics
1 answer:
alex41 [277]2 years ago
8 0

Answer: See below

Step-by-step explanation:

<u>Given:</u>

AB = CD and BC = DE

<u>To prove:</u>

AC = CE

            Statements                                       Reasons

  1. AB = CD                                                   Given
  2. AB + CB = CD + BC                Addition property of equality
  3. AB + BC = CD + DE                          Given: BC = DE
  4. AC = CE          By segment addition: AB + BC = AC and CD + DE = CE  

Therefore, AC = CE has been proved                

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d) (7b - 6a  + 9y) - (12b + 5a - 2y) =

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5 0
2 years ago
Please help me with this and I will give one of the answers most brainliest
inna [77]
A)

A=8\qquad\qquad B=12.5\\\\\\d(A,B)=|12.5-8|=|4.5|=\boxed{4.5\,\text{cm}}

b)

C=?\\\\\\d(C,A)=2\cdot d(C,B)\\\\|A-C|=2\cdot|B-C|\\\\|8-C|=2\cdot|12.5-C|\\\\&#10;|8-C|=|25-2C|\\\\\\8-C=25-2C\qquad\vee\qquad8-C=-(25-2C)\\\\-C+2C=25-8\qquad\vee\qquad8-C=-25+2C\\\\C=17\qquad\vee\qquad8+25=2C+C\\\\C=17\qquad\vee\qquad33=3C\quad|:3\\\\\boxed{C=17\qquad\vee\qquad C=11}

Mark 11 or 17.
4 0
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