B, that’s easy... Just add them up.
Answer:
-2x - 5 (lesser than or equal to) 15
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
If you are putting them all in order from least to greatest it would be 0.42, 1.3, 1.36, 1.63, 3.47,3.74. But, if you are separating them the first set of three numbers you wrote would be ordered 1.3, 1.36, 1.63. Then, the second set would be ordered 0.42, 3.47, 3.74. Hope this helped!!!
Answer with Step-by-step explanation:
Let F be a field .Suppose 
and 
We have to prove that a has unique multiplicative inverse.
Suppose a has two inverses b and c
Then, 
where 1 =Multiplicative identity
(cancel a on both sides)
Hence, a has unique multiplicative inverse.
