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3 years ago

Hey!Can someone solve my question??

Physics

2 answers:

tresset_1 [31]3 years ago

8 0

Answer:

223.38 C

Explanation:

according to gay lussacs law

p1/t1=p2/t2

so 2680/273.16=4870/t2

or t2=496.38 K

in celsius= 496.38-273=223.38 C

Mademuasel [1]3 years ago

4 0

Answer:

P1 = 2680 pa P2 = 4870pa

T1 = 273k T2 = T

From the ideal gas equation,

P1 / T1 = P2 / T2

2680 / 273 = 4870 / T

T = 4870 * 273 / 2860

T = 496.38 k

Kindly Mark Brainliest, Thanks

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yanalaym [24]

Answer:

$\theta=39.49^{\circ}$

Explanation:

Maximum height of the pumpkin, $H_{max}=9.99\ m$

Initial speed, v = 22 m/s

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$H_{max}=\dfrac{v^2\ sin^2\theta}{2g}$

On rearranging the above equation, to find the angle as :

$\theta=sin^{-1}(\dfrac{\sqrt{2gH_{max}}}{v})$

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3 years ago

Two samples of water are mixed together.

horrorfan [7]

Let the cold water go up x degrees.

Let the hot water go down 100 - x degrees.

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Givens

Ice

deltat = x

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Hot water

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m = 1.5 kg

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Formula

The heat up = heat down

0.50 * c * x = 1.5 * c * (100 - x) Divide both sides by c

Solution

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3 years ago

21. A 1000-kg automobile moving with a speed of 24 m/s relative to the road collides with a 500-kg automobile initially at rest.

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A truck is moving with less velocity in the direction in which the truck is moving earlier because the truck has more momentum.

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2 years ago

A rock is rolling down a hill. At position 1, its velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, its veloci

alukav5142 [94]

As this happens over twelve seconds, you would take the total difference in velocities and divide it by twelve to find the change per second

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4 0

3 years ago

Read 2 more answers

A container in the shape of a cube 10.0 cm on each edge contains air (with equivalent molar mass 28.9 g/mol) at atmospheric pres

Vikentia [17]

Answer:

a) m = 1.174 grams

b) F_g = 0.01151 N

c) F_c = 1013 N

Explanation:

Given:

- The length of a cube L = 10.0 cm

- The molar mass of air M = 28.9 g/mol

- Pressure of air P = 101.3 KPa

- Temperature of air T = 300 K

- Universal Gas constant R = 8.314 J/kgK

Find:

(a) the mass of the gas

(b) the gravitational force exerted on it

(d) Why does such a small sample exert such a great force? (6%)

Solution:

- Compute the volume of the cube:

V = L^3 = 0.1^3 = 0.001 m^3

- Use Ideal gas law equation and compute number of moles of air n:

P*V = n*R*T

n = P*V / R*T

n = 101.3*10^3 * 0.001 / 8.314*300

n = 0.04061 moles

- Compute the mass of the gas:

m = n*M

m = 0.04061*28.9

m = 1.174 grams

- The gravitational force exerted on the mass of gas is due to its weight:

F_g = m*g

F_g = 1.174*9.81*10^-3

F_g = 0.01151 N

- The force exerted on each face of cube is due its surface area:

F_c = P*A

F_c = (101.3*10^3)*(0.1)^2

F_c = 1013 N

- The molecules of a gas have high kinetic energy; hence, high momentum. When they collide with the walls they transfer momentum per unit time as force. Higher the velocity of the particles higher the momentum higher the force exerted.

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3 years ago