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For this case we first think that the skateboard and the child are one body.
We have then:
1 = jug
2 = skateboard + boy
By conservation of the linear amount of movement:
M1V1i + M2V2i = M1V1f + M2V2f
Initial rest:
v1i = v2i = 0
0 = M1V1f + M2V2f
Substituting values
0 = (7.8) (3.2) + (M2) (- 0.65)
0 = 24.96 + M2 (-0.65)
-24.96 = (-0.65) M2
M2 = (-24.96) / (- 0.65) = 38.4 kg
Then, the child's mass is:
M2 = Mskateboard + Mb
Clearing:
Mb = M2-Mskateboard
Mb = 38.4 - 1.9
Mb = 36.5 Kg
answer:
the boy's mass is 36.5 Kg
Answer:
Detailed explanation:
Density of water=1000kg/m³
Hence mass of water displaced is:
m=d×v
=1000kg/m³×(4.3×10^-3)m³ (volume of water displaced converted to L)
=4.3 kg of water
Hence, mass of football is also 4.3 kg(Archimedes principle)
Thus density of football
=mass÷volume
substitute the mass and volume and solve.
hope this helps
Answer:
I hope this helps a little bit.