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2 years ago

7

A gas occupies 13.2 L at a pressure of 2.36 atm. What is the pressure of the gas if the volume is 2.13 L and the temperature rem

ains unchanged?

1 answer:

Wewaii [24]2 years ago

5 0

Answer:

the pressure is to tight needs to be looser 13.2L of 2.36 and 2.13L

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Why a increase in volume causes a decrease in pressure

Sergio [31]

Answer:

If pressure increases, then volume decreases and vice versa, when temperature is held constant.” When pressure increases, the same number of molecules, or matter, are being forced closer together to occupy a shrinking space, their volume decreasing while their density correspondingly increases.

Explanation:

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4 years ago

The layer of the Earth called the mantle is often described as convecting. In this context, convection is

-Dominant- [34]

Answer:

the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.

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3 years ago

A 21.8 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature ris

Blababa [14]

<u>Answer:</u> The heat capacity of calorimeter is $15.66J/^oC$

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ethanol = 21.8 g

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

$\text{Moles of ethanol}=\frac{21.8g}{46.07g/mol}=0.473mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat released = ?

n = number of moles = 0.473 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -1235 kJ/mol = $-1235\times 10^3J/mol$ (Conversion factor: 1 kJ = 1000 J)

Putting values in above equation, we get:

$-1235\times 10^3J/mol=\frac{q}{0.473mol}\\\\q=(-1235\times 10^3J/mol\times 0.473mol)=-584.16\times 10^3J$

To calculate the heat capacity of calorimeter, we use the equation:

$q=c\Delta T$

where,

q = heat absorbed by the calorimeter = $584.16\times 10^3J$

c = heat capacity = ?

$\Delta T$ = change in temperature = $T_2-T_1=62.3^oC-25^oC=37.3^oC$

Putting values in above equation, we get:

$584.16\times 10^3J=c\times 37.3^oC\\\\c=\frac{584.16\times 10^3J}{37.3^oC}=15.66J/^oC$

Hence, the heat capacity of calorimeter is $15.66J/^oC$

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4 years ago

In general, how do the intermolecular attractions between particles in a gas compare with those between particles in a liquid?

Free_Kalibri [48]

In general the inter- molecular attraction between particles of gases is much more smaller than those found in the particles of liquids. Because of this, the particles of gases are usually far apart from one another while the particles of liquid are closer together compares to that of gases.

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3 years ago

How can you make a 250 ml 0.5 m solution of NaCl<br>show steps

GarryVolchara [31]

Answer:

Add water to 29.22 grams of salt until you get 1 liter of volume, stir it until the salt completely dissolves and mixes and voila! you will have a 0.5 M NaCl solution.

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4 years ago