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Gekata [30.6K]
2 years ago
10

Which open-sourced packet capture tool uses linux and mac os x operating systems?

Computers and Technology
1 answer:
Leto [7]2 years ago
5 0

Tcpdump is an open-sourced packet capture tool which uses Linux and Mac OS X operating systems.

<h3>What is tcpdump?</h3>

Tcpdump can be defined as an open-sourced packet capture tool that is typically used to monitor and record TCP/IP traffic that are passing through a network and most Unix-like operating systems such as Linux.

This ultimately implies that, tcpdump is an open-sourced packet capture tool which makes use of Linux and Mac OS X operating systems.

Read more on tcpdump here: brainly.com/question/14485515

#SPJ12

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What term is defined as software that allows users to use and adapt it for any purpose, often allowing the public to participate
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Answer:

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Explanation:

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What allows a programmer to write code quickly and efficiently for an action that must be repeated?
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Read 2 more answers
Computer Networks - Queues
lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time T_w in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w =  λ × T_w

r /  λ = w / λ  +  ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s  = \dfrac{1000}{64*1000}

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05    (i.e the average packet waiting time)

T_s = 0.015625

T_r =  0.05 + 0.015625

T_r =  0.065625

However; the  mean number of arrival per second λ is;

r = λ × T_r

λ = r /  T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus;  the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets  w waiting to be served is calculated using the formula

w =  λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0
3 years ago
#Write a function called find_median. find_median #should take as input a string representing a filename. #The file correspondin
azamat

Answer:

Explanation:

The following is written in Python. It takes in a file, it then reads all of the elements in the file and adds them to a list called myList. Then it sorts the list and uses the elements in that list to calculate the median. Once the median is calculated it returns it to the user. The code has been tested and the output can be seen in the image below.

def find_median(file):

   file = open(file, 'r')

   mylist = []

   for number in file:

       mylist.append(int(number))

   numOfElements = len(mylist)

   mylist.sort()

   print(mylist)

   if numOfElements % 2 == 0:

       m1 = numOfElements / 2

       m2 = (numOfElements / 2) + 1

       m1 = int(m1) - 1

       m2 = int(m2) - 1

       median = (mylist[m1] + mylist[m2]) / 2

   else:

       m = (numOfElements + 1) / 2

       m = int(m) - 1

       median = mylist[m]

   return median

print("Median: " + str(find_median('file1.txt')))

5 0
3 years ago
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