Answer:
The sugar would dissolve in water. You could then pour off the solution and wash the remaining sand with a bit more water. Heat the water to evaporate it from the sugar, and the two are separated.
Explanation:
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Answer: the surface area of the particles increases the number of the particle collisions
Explanation:
Answer:
Check explanation section.
Explanation:
Yes, that is true. Sodium with chemical symbol Na belongs to the group 1 on the periodic table. Group 1 elements are known as Alkali metals. Other elements in the group are Caesium, lithium, Rubidium, francium and potassium.
Neon belongs to the noble gas of group 8/0.
Sodium is very reactive and and good conductor of electricity. Sodium reacts with water for the production of hydrogen (NB: this reaction is vigorous).
2Na(s) + 2H2O ------------> 2NaOH + H2(g).
They can react with nonmetals such as the halogens. For instance;
Na + Cl2 -------------------------------> 2NaCl.
Sodium is ductile and have low melting point( but high compared to neon).
Neon is not active chemically and it has no odour and no color
Answer:
ΔT = 76.5 °C
Explanation:
Given data:
Amount of water = 100.0 g
Energy needed = 32000 J
Change in temperature = ?
Solution,
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
Q = m.c. ΔT
ΔT = Q / m.c
ΔT = 32000 j/ 100.0 g × 4.184 j/g. °C
ΔT = 32000 j / 418.4 j /°C
ΔT = 76.5 °C
Reduction Reaction:
Ag⁺ + 1e⁻ → Ag ------ (1)
Oxidation Reaction:
NO₂⁻ → NO₃⁻ + 2e⁻
Balance Oxygen atoms, by adding H₂O to side having less number of O atoms, and H⁺ to side having greater number of O atoms.
NO₂⁻ + H₂O → NO₃⁻ + H⁺ + 2e⁻
Balance the H⁺'s,
NO₂⁻ + H₂O → NO₃⁻ + 2 H⁺ + 2e⁻ ------ (2)
Multiply eq. 1 by 2 to balance the number of electrons in overall reaction.
2 Ag⁺ + 2e⁻ → 2 Ag ----- (3)
Compare eq. 2 and 3,
NO₂⁻ + H₂O → NO₃⁻ + 2 H⁺ + 2e⁻
2 Ag⁺ + 2e⁻ → 2 Ag
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NO₂⁻ + H₂O + 2 Ag⁺ → NO₃⁻ + 2 Ag + 2 H⁺
