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3 years ago

WILL GIVE BRAINLIEST!!!

2 answers:

7 0

Hey there!:

ΔTf = Kf * m

Molar mass glucose = 180 g/mol

number of moles glucose:

n = mass of solute / molar mass

n = 21.5 / 180

n = 0.119 moles glucose

Amount of solvent in kg = 255/1000 = 0.255 Kg

Molality = number of moles / solvent

m = 0.119 / 0.255

m = 0.466 moles/kg

Kf for water = - 1.86 ºC/*m

Therefore:

ΔTf = Kf * m

ΔTf = (-1,86) * 0.466

ΔTf = -0.86676 ºC

hope this helps!

max2010maxim [7]3 years ago

7 0

ΔTf = Kf * m Molar mass glucose = 180 g/molthe number of moles glucose:n = mass of solute / molar massn = 21.5 / 180n = 0.119 moles glucoseAmount of solvent in kg = 255/1000 = 0.255 Kg Molality = number of moles / solventm = 0.119 / 0.255 m = 0.466 moles/kgKf for water = - 1.86 ºC/*mTherefore:ΔTf = Kf * m ΔTf = (-1,86) * 0.466ΔTf = -0.86676 ºC

this is to the best of my brain power and i hope this helps with your problem

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2 years ago

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$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

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Molarity of solution = 0.011 M

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Putting values in above equation, we get:

$0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol$

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

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