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Romashka [77]
3 years ago
9

OMG PLEASE HELP ME :(

Chemistry
1 answer:
dusya [7]3 years ago
6 0

Answer:

D) The gravity on the moon is one sixth the gravity of Earth.  

Explanation:

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A helium filled balloon has a volume of 2.48L and a pressure of 150kpa the volume of the balloon increases to 2.98L what is the
Natali [406]

Answer:

THE NEW PRESSURE OF THE HELIUM GAS IS 124kPa AFTER THE VOLUME WAS INCREASED FROM 2.48 L TO 2.98 L

Explanation:

Using Boyle's law which states that at constant temperature, the pressure of a given gas is inversely proportional to the volume occupied by the gas.

Mathematically,

P1 V1 = P2 V2

P1 = 150 kPa = 150 * 10^3 Pa

V1 = 2.48 L

V2 = 2.98 L

P2 = ?

Rearranging the formula making P2 the subject of the equation, we obtain;

P2 = P1 V1 / V2

P2 = 150 * 10^3 * 2.48 / 2.98

P2 = 372 * 10 ^3 / 2.98

P2 = 124.83 * 10^3 Pa or 124.8kPa

In other words, the new pressure of the helium gas after its volume was increased from 2.48 L to 2.98 L is 124.8kPa.

5 0
3 years ago
What are three ways of measuring the amount of substance?
Rashid [163]

Answer:

Measure its mass

Measure its volume

Measure its number of moles

Explanation:

3 0
2 years ago
Which of the following could not happen to an igneous rock?
galben [10]
I could not break unless you hit it with a sledge hammer
4 0
3 years ago
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
A. Electrons have a charge of_____
Dmitry [639]
Electrons: negative
Protons: positive
Neutrons: nuetral
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