All categories

3 years ago

OMG PLEASE HELP ME :(

Chemistry

1 answer:

dusya [7]3 years ago

6 0

Answer:

D) The gravity on the moon is one sixth the gravity of Earth.

Explanation:

You might be interested in

NaOH+HCl->............

Oxana [17]

Answer:

NaCl+H20

Explanation:

It is a neutralisation reaction in which NaOH is a base and HCl is an acid. On reaction it forms salt and water.

Please mark as brainliest

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME If a radioactive substance has an initial mass of 50 grams

Yuri [45]

Answer: $3.125\ g$

Explanation:

Given

Initial mass $A_o=50\ g$

half-life is $T_{\frac{1}{2}}=5\ years$

At any time the left amount is given by

$A=A_o2^{-\dfrac{t}{T_{\frac{1}{2}}}}\\\\\text{Insert the values}\\\\A=50\cdot 2^{-\dfrac{20}{5}}\\\\A=50\cdot 2^{-4}\\\\A=\dfrac{50}{16}\\\\A=3.125\ g$

3 0

3 years ago

What is composed of two different atoms?

Evgen [1.6K]

Answer: When atoms combine through chemical bonding, they form compounds—unique structures composed of two or more atoms. The basic composition of a compound can be indicated using a chemical formula.

Hope I was able to help! Mark me brainly it would help a lot!:)

8 0

3 years ago

The titration of 25.0 ml of an iron(ii) solution required 18.0 ml of a 0.205 m solution of dichromate to reach the equivalence p

sasho [114]

The formula of this is : MV = MV or Molarity × Volume = Molarity × Volume. So you do:
25X = 18×.205=.1476M

6 0

3 years ago

A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600.mL at 1.0atm. To prepare for ignition of

Ket [755]

12 atm is the new pressure of the air‑fuel mixture when A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600 ml at 1.0atm and final volume of 50 ml.

Explanation:

Data given:

The air fuel mixture is assumed to be having ideal behaviour

initial volume of gaseous air fuel mixture V1 = 600 ml

initial pressure of gaseous air fuel mixture P1= 1 atm

final volume when piston is removed, V2= 50 ml

final pressure of the gaseous air mixture, P2 = ?

Applying the Boyle's Law,

P1V1 = P2V2

rearranging the equation:

P2 = $\frac{P1V1}{V2}$

putting the value in the equation,

P2 = $\frac{600 X 1}{50}$

P2 = 12 atm

the pressure is increased to 12 atm when volume is reduced to 50 ml.

7 0

4 years ago