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Assoli18 [71]
3 years ago
6

Rank the following carboxylic acids by acid strength, with the strongest at the top and the weakest at the bottom. It may help t

o draw each Lewis structure. Drag and drop options into correct order.For keyboard navigation...SHOW MORE Press space or enter to grab A. CF3CO2H B. CHF2CO2HC. CH2FCO2H D. CH3CO2H
Chemistry
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

$CF_3CO_2H> CHF_2CO_2H>CH_2FCO_2H>CH_3CO_2H$

Explanation:

Florine has the highest electronegativity and it thus pulls the element of $OH^- groups in the COOH group towards itself, making it relatively easy to loose the proton of the carboxyl group.

       F     O

       ↑     ||

 F← C ← C ← O - H             ,  Here three Florine withdraw

       ↓

       F

        F     O

       ↑     ||

 F← C ← C - O  H             ,  Here two Florine withdraw

       ↓

       H

        F   O

        |     ||

 H - C - C - OH             ,  Here one Florine withdraw

       ↓

       H

       H   O

        |     ||

 H - C - C - OH             ,  Here no Florine withdraw

        |

       H

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Answer:
           One: <u>Selenium</u> is Paramagnetic

Explanation:
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Electronic configuration of Scandium;

Sc  =  21  = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹

Sc³⁺  =  1s², 2s², 2p⁶, 3s², 3p⁶ 

Hence in Sc³⁺ there is no unpaired electron.

Electronic configuration of Bromine;

Br  =  35  = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁵

Br⁻  =  1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶

Hence in Br⁻ there is no unpaired electron.

Electronic configuration of Magnesium;

Mg  =  12  = 1s², 2s², 2p⁶, 3s²

Mg²⁺  =  1s², 2s², 2p⁶

Hence in Mg²⁺ there is no unpaired electron.

Electronic configuration of selenium;

Se  =  34  = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁴

Or,

Se  =  34  = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4px², 4py¹, 4pz¹

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8 0
3 years ago
Help! please! hurry! I will mark brainliest if you get it correct!! NO SPAM!!!!!!
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Answer: 5.747 * 10^14 Hz

Explanation:

Convert 522nm to m = 522 * 10^-9 m (since 1nm=10^-9m)

If c = wavelength * frequency, where c is the speed of light (3.0 * 10^8 m/s), then you can manipulate the equation to solve for frequency (f).

f = c / wavelength

Plug in the given numbers:

f = (3.0 * 10^8) / (10^-9)

f = 5.747 * 10^14 Hz

4 0
2 years ago
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meriva

Answer:

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Explanation:

The dilution equation can be used to relate the concentration C₁ and volume V₁ of the stock/undiluted solution to the concentration C₂ and volume V₂ of the diluted solution:

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