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3 years ago

15

What was the name for the secret code used by many alchemists?

1 answer:

ahrayia [7]3 years ago

5 0

Answer:

A. Zodiac

B. Palingenesis

C. Palabra mysteria

D. Decknamen

The correct answer is D. Decknamen.

Explanation:

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romeo is upset that he'll no longer be able yo see juliet, but this living creature will be able to see her, be near her, even f

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Answer:

beautiful and beautiful home on

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3 years ago

Read 2 more answers

Why are polyatomic called radicals

Digiron [165]

That’s because when a charged chemical species composes of two or more atoms (covalently bonded), they act as a single unit. the term radicals refers to free radicals that are with an unpaired electron and because not all of its electrons are found in pairs

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2 years ago

An aluminum cup of 140 cm3 capacity is completely filled with glycerin at 20°C. How much glycerin will spill out of the cup if t

mel-nik [20]

Explanation:

The given data is as follows.

coefficient of volume expansion of glycerin ( $\beta$ ) = $5.1 \times 10^{-4} 1/^{o}C$

linear expansion coefficient of aluminum, $(\alpha_{A})$ = $23 \times 10^{-6} 1/^{o}C$

Volume = 100 $cm^{3}$

The increase in volume of the cup will be calculated as follows.

$\Delta V_{c} = V \times 3 \times \alpha \times \Delta T$

= $100 cm^{3} \times 3 \times 23 \times 10^{-6} \times (31 - 20)^{o}C$

= $75900 \times 10^{-6} cm^{3}$

= 0.0759 $cm^{3}$

Formula for increase in volume of glycerine is as follows.

$\Delta V_{g} = V \times \beta_{g} \times \Delta T$

= $100 cm^{3} \times 5.1 \times 10^{-4} 1/^{o}C \times (31 - 20)^{o}C$

= 0.5610 $cm^{3}$

Therefore, volume of glycerin spilled is calculated as follows.

$\Delta V = \Delta V_{g} - \Delta V_{c}$

= (0.5610 - 0.0759) $cm^{3}$

= 0.4851 $cm^{3}$

Thus, we can conclude that 0.4851 $cm^{3}$ glycerin will spill out of the cup.

6 0

3 years ago

2. The table below shows the atomic numbers of elements of the periodic table represented by letters I to Q The letters are not

Komok [63]

Explanation:

cudhdbsieehe eirbruwnee8ebeuw eodjsuww8

4 0

2 years ago

helium gas in a 2.00 L cylinder is under 1.12 atm pressure. At 36.5°C that same gas sample has a pressure of 2.56 atm. What was

Irina18 [472]

Answer:

T₁ = 135.41 K

Explanation:

Given data:

Initial pressure = 1.12 atm

Finial temperature = 36.5 °C (36.5 +273 = 309.5 K)

Initial temperature = ?

Final pressure = 2.56 atm

Formula:

P₁/T₁ = P₂/T₂

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure

T₂ = Final temperature

Solution:

P₁/T₁ = P₂/T₂

T₁ = P₁T₂ /P₂

T₁ = 1.12 atm × 309.5 K / 2.56 atm

T₁ = 346.64 atm . K / 2.56 atm

T₁ = 135.41 K

5 0

3 years ago