Is 320 g per 100 g of water.
Answer:
E = 1.2443*10⁶ N/C
Explanation:
R = 41.6 cm = 0.416 m
Q₁ = 8.55 μC = 8.55*10⁻⁶C
Q₀ = 4.43 μC = 4.43*10⁻⁶C
r = 17.9 cm = 0.179 m
K = 9*10⁹ N*m²/C²
Since r < R we can apply Gauss's Law as follows
E = K*Q₀ / r²
⇒ E = (9*10⁹ N*m²/C²)*(4.43*10⁻⁶C) / (0.179 m)²
⇒ E = 1.2443*10⁶ N/C
Yes. If this is the balanced equation:
AlCl3 + 3Na —— 3NaCl + Al
then Al was reduced from a 3+ oxidation (to neutralize the 3- from the chlorine) to a 0 oxidation (elemental ground state).
Answer:
5Fe⁺² + MnO₄⁻ + 8H⁺ => 5Fe⁺³ + Mn⁺² + 4H₂O
Explanation:
Fe⁺² + MnO₄⁻ + H⁺ => Mn⁺² + Fe⁺³ + H₂O
5(Fe⁺² => Fe⁺³ + 1e⁻) => 5Fe⁺² => 5Fe⁺³ + 5e⁻
<u>MnO₄⁻ + 5e⁻ => Mn⁺² => MnO₄⁻ + 8H⁺ + 5e⁻ => Mn⁺² + 4H₂O</u>
=> 5Fe⁺² + MnO₄⁻ + 8H⁺ => 5Fe⁺³ + Mn⁺² + 4H₂O
Answer:
she should not have multiplied the sulfur atoms by the subscript 4
Explanation:
