<u>We are given:</u>
Mass of water: 119 grams
We know that one mole of a gas occupies 22.4L of volume
<u>Number of moles of water:</u>
Number of moles = given mass / Molar mass
Number of moles = 119 / 18 [molar mass of water = 18 grams/mol]
Number of moles = 6.61 moles
<u>Volume occupied:</u>
Volume = number of moles * 22.4 L
Volume = 6.61 * 22.4
Volume = 148L
Volume (in mL) = 1.48 * 10⁻¹ mL
A condensation reaction forming a glycosidic bond. so in other words a monosaccharide joining together to form a disaccharide.
Answer:

Explanation:
The expression for the work done is:

Where,
W is the amount of work done by the gas
R is Gas constant having value = 8.314 J / K mol
T is the temperature
P₁ is the initial pressure
P₂ is the final pressure
Given that:
T = 300 K
P₁ = 10 bar
P₂ = 1 bar
Applying in the equation as:



