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masha68 [24]
2 years ago
15

A planet has a circular orbit around a star. It is a distance of 81,000,000 km from the centre of the star. It orbits at an aver

age speed of 46,000 km/h. How many Earth days does it take the planet to orbit the star? Give your answer to 2 sf.
Mathematics
1 answer:
slava [35]2 years ago
5 0

81,000,000 \text{ km} \left(\frac{1 \text{ h}}{46,000 \text{ km}} \right) =\frac{40500}{23} \text{ h} \\ \\ \frac{40500}{23} \text{ h} \left(\frac{1 \text{ days}}{24 \text{ hours}} \right) \approx \boxed{73 \text{ days}}

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The missing side length is 7.2 rounded to the nearest tenth
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3 years ago
Ingrid spends $120 on car repairs. Which integer represents the amount of money Ingrid must earn in order to create a zero pair?
Julli [10]

Answer: -120

Step-by-step explanation:

this would be the answer because if you take a positive and add it to a negative you get zero if their the additive inverse of the number.

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2 years ago
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3 years ago
An object travels along a circular path so that it completes one revolution in 8 seconds. If the linear velocity of the object i
natima [27]

Answer:

Using the concept of speed-distance-time, we find that the diameter of the circular path is 12 inches.

Step-by-step explanation:

Given that the object completes one revolution in 8 seconds. So, the circular speed of the object is 2πr/8 = πr/4 inches per seconds, where r is the radius of the circular path. The speed can be written as:

πr/4 inches per seconds = 60πr/4 inches per minute = 15πr inches per minute.

But, it is given that the circular speed of the object is 90π inches per minute. So,

90π = 15πr

r = 6 inches

Since, diameter is the double of radius, d = 2r = 12 inches.

For more explanation, refer the following link:

brainly.com/question/17978382

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4 0
2 years ago
Find the distance between the two given points. (-6, -5) and (2, 0)
Ipatiy [6.2K]

Answer:

The answer is

<h2>\sqrt{41}  \:  \:  or \:  \:  \: 6.403 \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{( {x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-6, -5) and (2, 0)

The distance is

d =  \sqrt{ ({ - 6 - 2})^{2} +  ({ - 5 - 0})^{2}  }  \\  =  \sqrt{ ({ - 4})^{2}  +  ({ - 5})^{2} }  \\  =  \sqrt{16 + 25}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

\sqrt{41}  \:  \:  or \:  \:  \: 6.403 \:  \:  \: units

Hope this helps you

4 0
3 years ago
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