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2 years ago

What is the value of x in the figure below? In this diagram, ABD ~ CAD.

Mathematics

1 answer:

Shalnov [3]2 years ago

3 0

Answer:

The Answer above On The Image

Step-by-step explanation:

thanks……………………………………………

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help Video If you place a 40-foot ladder against the top of a building and the bottom of the ladder is 17 feet from the bottom o

irina [24]

Answer: the building is about 63 feet

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3 years ago

Please help this is due today!!!!!

Bad White [126]

Answer:

x=15

y=36

P=200

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

You worked theses hours this week: 1 1/2 , 2 3/4, 3 3/4, 5 1/2

alukav5142 [94]

Answer: 13.5 hours.

I got the answer by simply adding up the integers to start with.

Integers = 1, 2, 3 and 5.

The integers added up equal to 11.

Next we add up the remaining fractions.

Fractions = 1/2, 3/4, 3/4 and 1/2.

We can add up 1/2 and 1/2 to equal 1, and 3/4 and 3/4 to make 1.5.

1 + 1.5 = 2.5

Finally, we add up the answer for the integers and the fractions together, (11 + 2.5) which equals 13.5.

Our answer is 13.5 hours.

(Not sure why the answer isn't in the choices)

6 0

3 years ago

Need help fast will give brainliest!!!!!

Fofino [41]

Answer:

C and E i think

Step-by-step explanation:

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3 years ago

Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

2 years ago