Answer:
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D. Ionic compound
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Answer:
V = 267.2 L
Explanation:
Given data:
Volume of balloon = ?
Mass of helium = 2.50 g
Temperature of gas = 180°C
Pressure = 0.87 atm
Solution:
Number of moles of helium:
Number of moles = mass/molar mass
Number of moles = 2.50 g/ 4 g/mol
Number of moles = 0.625 g
Volume of helium:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
0.87 atm× V = 0.625 mol × 0.0821 atm.L/mol.K×453 K
V = 232.45 atm.L /0.87 atm
V = 267.2 L
Answer:
20.93 g
Explanation:
From the question given above, the following data were obtained:
Heat (Q) = 3.5 KJ
Initial temperature (T₁) = 26°C
Final temperature (T₂) = 66°C
Mass (M) =?
Next, we shall convert 3.5 KJ to J. This can be obtained as follow:
1 KJ = 1000 J
Therefore,
3.5 KJ = 3.5 KJ × 1000 J / 1 KJ
3.5 KJ = 3500 J
Next, we shall determine the change in the temperature of the water. This is illustrated:
Initial temperature (T₁) = 26°C
Final temperature (T₂) = 66°C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 66 – 26
ΔT = 40 °C
Finally, we shall determine the mass of the water. This can be obtained as follow:
Heat (Q) = 3500 J
Change in temperature (ΔT) = 40 °C
Specific heat capacity (C) = 4.18 J/gºC
Mass (M) =?
Q = MCΔT
3500 = M × 4.18 × 40
3500 = M × 167.2
Divide both side by 167.2
M = 3500 / 167.2
M = 20.93 g
Therefore, the mass of the water is 20.93 g
Answer:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O
Explanation:
The reaction above is simply termed combustion reaction in which an organic compound react with oxygen to produce carbon dioxide and water. Thus, we can obtain the balanced equation for the reaction reaction as follow:
C₈H₁₈ + O₂ —> CO₂ + H₂O
There are 8 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 8 before CO₂ as shown below:
C₈H₁₈ + O₂ —> 8CO₂ + H₂O
There are 18 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 9 before H₂O as shown below:
C₈H₁₈ + O₂ —> 8CO₂ + 9H₂O
There are 2 atoms of O on the left side and a total of 25 atoms on the right side. It can be balance by writing 25/2 before O₂ as shown below:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
Thus, the equation is balanced!
The above equation can also be written as follow:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
Multiply through by 2
2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O